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The x-intercepts are the x-values of the points where the graph intercepts the x-axis.
Graph:
x-intercepts: x≈-1.15, x=0, x≈1.65, and x≈3.79.
Local Maximum: (0.87,2.78)
Local Minimums: (-0.68,-2.31) and (3.02,-9.30)
Increasing Interval: -0.68<x<0.87 and x>3.02
Decreasing Interval: x<-0.68 and 0.87<x<3.02
To begin, we will use a table of values to draw the graph. Then, using that table we will state x-intercepts, and any local maximum(s) and minimum(s), as well as the increasing and decreasing intervals of the function.
We want to find the x-intercepts, and the local minimum and maximum. Let's think about what these terms mean and then obtain the desired information.
x-intercepts | Relative minimums and maximums | |
---|---|---|
Definition | x-coordinates of the points at which the graph intercepts the x-axis | The lowest and highest point for a region of the graph. |
In the Given Function | x≈-1.15, x=0, x≈1.65, and x≈3.79 | (0.87,2.78), (-0.68,-2.31), and (3.02,-9.30) |
A local maximum is the point where the function goes from increasing interval to decreasing interval. A local minimum is the point where the function goes from decreasing interval to increasing interval.
To determine the intervals for which the function is increasing, decreasing, and constant, let's consider the graph of the function as we move along it in the positive x-direction.
To graph the function, we will use a table to plug in x-values and get the corresponding y-values.
x | 0.7x4−3x3+5x | f(x)=0.7x4−3x3+5x |
---|---|---|
-1 | 0.7(-1)4−3(-1)3+5(-1) | -1.3 |
0 | 0.7(0)4−3(0)3+5(0) | 0 |
1 | 0.7(1)4−3(1)3+5(1) | 2.7 |
3 | 0.7(3)4−3(3)3+5(3) | -9.3 |
We will now plot the obtained points in a coordinate plane and connect them with a non-linear line.