Big Ideas Math Algebra 1, 2015
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Big Ideas Math Algebra 1, 2015 View details
Chapter Review
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Exercise 7 Page 282

8 brushes, 4 tubes of paint

Practice makes perfect
We are given the total expenses of $20. We are also told that the tubes of paint cost $4 and the paintbrushes $0.50. Let's start by writing the first equation using verbal expressions. price per tube of paint* number of tubes + price per paintbrush * number of brushes = total cost If we let t represent the number of tubes of paint and p represent the number of paintbrushes, we can write this equation algebraically. $4* t+ $0.50* p= $20Having that done, we can move on to the second equation. Since we buy twice as many brushes as tubes of paint, we have to multiply the number of tubes of paint by 2, then equate it to the number of paintbrushes. 2* number of tubes of paint = number of paintbrushes We have to use the same variables, t and p as in the first equation. 2* t= p Now, we can combine both equations into a system of equations. 20=4t+0.50p & (I) 2t=p & (II) Since variable p in the second equation is already isolated, it might be a good idea to solve the system by substitution
20=4t+0.50p & (I) 2t=p & (II)
20=4t+0.50( 2t) & (I) 2t=p & (II)
20=4t+t & (I) 2t=p & (II)
20=5t & (I) 2t=p & (II)
4=t & (I) 2t=p & (II)
t=4 & (I) 2t=p & (II)
We have calculated that t=4, let's substitute it into the second equation and find the value of p.
t=4 & (I) 2t=p & (II)
t=4 & (I) 2( 4)=p & (II)
t=4 & (I) 8=p & (II)
t=4 & (I) p=8 & (II)
The solution to the system is t=4 and p=8. In the context of the problem, it means that we buy 4 tubes of paint and 8 paintbrushes.