Big Ideas Math Algebra 1, 2015
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Big Ideas Math Algebra 1, 2015 View details
5. Solving Compound Inequalities
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Exercise 25 Page 86

Split the compound inequality into two separate inequalities.

No solution.

Practice makes perfect
We were asked to solve a compound inequality. Let's start by splitting it into separate inequalities. Compound Inequality:& 22< -3c+ 4 < 14 First Inequality:& 22< -3c+ 4 Second Inequality:& -3c+ 4 < 14 Notice that compound inequalities written in this way are equivalent to compound inequalities that involve the word and. 22< -3c+ 4 and -3c+ 4 < 14

Let's solve the inequalities separately.

First Inequality

Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. The only difference is that when you divide or multiply by a negative number, you must flip the inequality sign.
22< -3c+ 4
18< -3c
-6>c
c<-6
This above tells us that all values less than - 6 will satisfy the inequality.
Strict Inequality

Note that the point on - 6 is open because it is not included in the solution set.

Second Inequality

Once more, we will solve the inequality by isolating the variable.
-3c+ 4 < 14
-3c<10
c>-10/3
This inequality tells us that all values greater than - 103 will satisfy the inequality.
Strict Inequality

Note that the point on - 103 is open because it is not included in the solution set.

Compound Inequality

The solution set to the compound inequality is the intersection of the solution sets. To help visualize the algebraic expression, we will write c>- 103 as - 103cannot be greater than - 103 and less than -6 simultaneously, the compound inequality does not have a solution.