{{ item.displayTitle }}

No history yet!

Student

Teacher

{{ item.displayTitle }}

{{ item.subject.displayTitle }}

{{ searchError }}

{{ courseTrack.displayTitle }} {{ statistics.percent }}% Sign in to view progress

{{ printedBook.courseTrack.name }} {{ printedBook.name }}
The point-slope form is written as $y−y_{1}=m(x−x_{1}).$
From the exercise we know the slope $-3,$ which is $m$. The coordinates $(2,13)$ are $x_{1}$ and $y_{1}.$ Put them into the form to get the line's equation in point-slope form.
$y−13=-3(x−2)$
Now, we just have to solve for $y$ and simplify in order to rewrite the equation in its slope-intercept form.
The point-slope form and slope-intercept form are written the line as $y−13=-3(x−2)andy=-3x+19.$

$y−13=-3(x−2)$

AddEqn$LHS+13=RHS+13$

$y=-3(x−2)+13$

DistrDistribute $-3$

$y=-3x+6+13$

SimpTermsSimplify terms

$y=-3x+19$