Writing Linear Equations in Point-Slope Form

The point-slope form is written as $$y-y_1=m(x-x_1).$$ From the exercise we know the slope $\text{-}3,$ which is $m$. The coordinates $(2,13)$ are $x_1$ and $y_1.$ Put them into the form to get the line's equation in point-slope form. $$y-13=\text{-}3(x-2)$$ Now, we just have to solve for $y$ and simplify in order to rewrite the equation in its slope-intercept form. The point-slope form and slope-intercept form are written the line as $$y-13=\text{-}3(x-2)\text{and}y=\text{-}3x+19.$$