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| 15 Theory slides |
| 15 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Transformations are useful to describe the relationship between two figures. This lesson will discuss two particular types of transformations: translations and reflections.
Here are a few recommended readings before getting started with this lesson.
A transformation is a function that changes a figure in a particular way — it can change the position, size, or orientation of a figure. The original figure is called the preimage and the figure produced is called the image of the transformation. A prime symbol is often added to the label of a transformed point to denote that it is an image.
Zain's parents want to renovate their backyard. The lot is pretty wide and, once the weeds are taken care of, it could be used for plenty of things. The first thing that comes to Zain's mind is to put in a pool, so they make a sketch of the backyard to show their idea to their parents. They use the letter P to represent the pool.
Zain's dad says that the pool should not be right against the gate to the backyard, so he suggests two possible alternatives, P1 and P2.
A pure translation takes a preimage P and makes it into an image that is congruent and has the same orientation as P. In the sketch, both P1 and P2 are congruent to P, so all that remains is to determine which image has the same orientation as P. Notice that the longest side of P is horizontal in the sketch.
This preimage will now be compared to images P1 and P2. The longest side of image P1 is vertical in the sketch, so it does not have the same orientation as P. This means that P1 is not a pure translation of P. On the other hand, P2 matches P exactly.
Since P2 is congruent to P and has the same orientation, it is a pure translation of P.
The a value of the translation corresponds to the horizontal displacement of the translation, while the b value is the vertical displacement. Since every point of the preimage is translated in the same way, any particular corner of the pool can be used along with the grid to find a and b. Just keep in mind that they have to be matching corners!
The horizontal displacement is 4 units to the right, so a=4. Likewise, the vertical displacement is 7 units up, so b=7.
In the following applet, △ABC is translated to map onto △A′B′C′. Write the a and b values of the translation.
The renovations are now taking place, so there is a lot going on in the backyard. During the morning, Zain's mom goes out to water some plants that were on a planter pot when she noticed that they are in the wrong place.
The planter was probably in the way when the builders were working on the pool. However, the plants need to be in the correct spot to get just the right amount of sunlight, so she kindly requests the workers to put them back where they belong when they are finished for the day. To find the original position of the pots, Zain placed a coordinate plane on the backyard plans.
Find the initial coordinates of the pot. To translate it 7 units to the left and 1 unit up, subtract 7 from the x-coordinate and add 1 to the y-coordinate.
Zain's mom wants the builders to return the planter pot back to where it was, which they can do by translating it 7 units to the left and 1 unit up. Begin by finding the current coordinates of the pot.
Once the pool was installed, Zain went to take a look at it. They noticed a unique pattern printed in the pool tiles.
Zain thinks of this as a transformation and writes the following labels for the vertices of both figures.
Draw segments that connect every point of the preimage with its corresponding point in the image — for example, CC′. The line of reflection is the perpendicular bisector of any segment connecting a point to its image.
When a point is reflected across a line, its image is such that the line of reflection is the perpendicular bisector of the segment that connects the point to its image. To find the line of reflection of the pool tiles, start by drawing a segment that connects a vertex and its image. For instance, draw CC′.
Next, construct the perpendicular bisector of CC′. This will represent the line of reflection used to make the pattern in the pool tiles.
With this, the line of reflection can be finally drawn.
The measuring tool is useful for finding the midpoint between a point and its image. Place the ends of the measuring tool on a point and its corresponding image.
Next, move the middle point so that the angle of the measuring tool is 180∘ and the length of both segments is equal. This will make sure the middle point lies on the line of reflection.
Repeat this process on another pair of corresponding vertices to find a second point that lies on the line of reflection.
Now that two points that lie on the line of reflection have been identified, that line can be drawn.
Place points A′, B′, and C′ where they should be to reflect △ABC across the given line. The measuring tool can be used to find segments perpendicular to the line of reflection.
It is always a good idea to have a picnic table close to the pool for snacks and drinks and to hang out while drying off, so Zain added this to the sketch, along with two chairs.
Zain noted that the table is placed along the x-axis they drew when trying to figure out where to return the planter pot.
Two more chairs are to be placed so that they are reflections across the x-axis of the currently shown chairs.
Start by finding the coordinates of the left chair.
The right chair can also be reflected by following the same procedure.
The following graph shows the image of a point P after a translation.
Let's take a look at the given point.
We are told that this point P' is the image of a point P after a translation 5 units right and 2 units down. We do not know the coordinates of P, so we will let them be (x,y). We can write the translation using translation notation. (x,y) → (x + 5,y - 2) We know that the image of P after the translation is P'(3,0). (x+5,y-2) = (3,0) This lets us write and solve an equation for each coordinate. Let's write and solve the equation for the x-coordinate first.
Let's find the y-coordinate of the preimage next.
This means that the coordinates of the preimage P before the translation are P(-2,2).
Another way of finding the preimage is by reversing the translation. Point P' is the image of point P after a translation 5 units right and 2 units down. To reverse the translation, we just reverse the directions of the translation while keeping the number of units. 5 units right &→ 5 units left 2 units down &→ 2 units up Let's see how the translation would look!
The following diagram shows the image △A′B′C′ after it was translated 3 units left and 1 unit up.
Consider the given triangle.
We are told that this triangle is the image of a triangle ABC after a translation 3 units left and 1 unit up. We want to determine the coordinates of the vertex C of the preimage before the translation. Let's focus on vertex C'.
Since we do not know the coordinates of point C, we will write them as (x,y). Let's write this translation using translation notation. (x,y) → (x - 3,y + 1) We know that the image of C after the translation is C'(-1,-1). (x-3,y+1) = (-1,-1) This lets us write and solve an equation for each coordinate. Let's write and solve the equation for the x-coordinate first.
Let's find the y-coordinate of the preimage next.
We found that x=2 and y=-2. This means that point C of the preimage before the translation is C(2,-2).
Another way of finding the preimage is by reversing the translation. Point P' is the image of point P after a translation 5 units right and 2 units down. To reverse the translation, we just reverse the directions of the translation while keeping the number of units. 3 units left &→ 3 units right 1 unit up &→ 1 unit down Let's see how the translation would look!
Consider the given triangle.
Let's begin by identifying the coordinates of the vertices of the given triangle.
To reflect a figure over the y-axis, we can simply change the sign of the x-coordinates of the figure.
Vertices of △ ABC | Vertices of △ A'B'C' |
---|---|
A(-1,2) | A'(1,2) |
B(-1,-2) | B'(1,-2) |
C(1,0) | C'(-1,0) |
This means that the coordinates of the image after the reflection over the y-axis are A'(1,2), B'(1,-2), and C'(-1,0). Let's finish by drawing the image!
Consider the given triangle.
Let's begin by labeling the coordinates of the vertices of the given triangle.
We can reflect a figure over the x-axis by simply changing the sign of the y-coordinates of the figure.
Vertices of △ ABC | Vertices of △ A'B'C' |
---|---|
A(-3,2) | A'(-3,-2) |
B(1,1) | B'(1,-1) |
C(0,-1) | C'(0,1) |
We found that the coordinates of the image after the reflection over the x-axis are A'(-3,-2), B'(1,-1), and C'(0,1). Finally, let's draw the image after the reflection.