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| Student Learning Objectives: |
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| | 16 Theory slides |
| | 8 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Consider a rectangle ABCD. Can the rectangle be rotated such that the image exactly matches the preimage? Not so fast, there is one catch; can it be done where the angle of rotation is greater than 0^(∘) and less than 360^(∘)? Try it out by rotating ABCD around the movable point P.
For some geometric figures, it is possible to find a transformation that maps the figures onto themselves. In such cases, the transformation is called a symmetry of the figure.
When a figure is rotated less than 360^(∘), the final image can look the same as the initial one — as if the rotation did nothing to the preimage. In such a case, the figure is said to have rotational symmetry.
A figure in a plane has rotational symmetry if the figure can be mapped onto itself by a rotation between 0^(∘) and 360^(∘) about the center of the figure. This point is called the center of symmetry. When a figure has rotational symmetry, it is said to be rotationally symmetric.
While walking downtown, Heichi and Paulina saw a store with the following logo. They began to discuss whether the logo has rotational symmetry. To figure it out, they went into the store and took a business card each.
At their respective homes, and using patty paper, each performed rotations on the logo. The same night, Heichi called Paulina to tell her that the logo is rotationally symmetric, but Paulina disagreed. Who is correct?
In the event that the figure has rotational symmetry, what is the order of symmetry?
As shown, a rotation of 120^(∘) maps the logo onto itself. Therefore, the logo is rotationally symmetric, which means Heichi was right. Additionally, two other rotations of 240^(∘) and 360^(∘) also map the logo onto itself. This means that the order of symmetry is 3.
In the first exploratory applet, it was studied whether a rectangle has rotational symmetry. Now, a parallelogram will be studied. Consider a parallelogram ABCD.
Does it have rotational symmetry?
As shown, a rotation of 180^(∘) about the intersection point of diagonals maps the parallelogram onto itself. Consequently, it is rotationally symmetric.
The first point implies that the measures of ∠ A and ∠ C are equal and the measures of ∠ B and ∠ D as well. Therefore, in a parallelogram, the opposite angles are congruent angles. ∠ A ≅ ∠ C ∠ B ≅ ∠ D Similarly, the second point implies that the lengths of AB and CD are equal and the lengths of BC and DA as well. Therefore, in a parallelogram, the opposite sides are congruent segments. AB ≅ CD BC ≅ DA On the parallelogram, these congruences can be represented as follows.
The symmetries of a figure help determine the properties of that figure. For instance, since a parallelogram has 180^(∘) rotational symmetry, its opposite sides and angles will match when rotated 180^(∘), which allows for the establishment of the following property.
The opposite sides and angles of a parallelogram are congruent.
Symmetries can be used to characterize classes of figures. For example, all parallelograms have 180^(∘) rotational symmetry. The same is true for rectangles, rhombi, and squares.
Is there another type of symmetry apart from the rotational symmetry? The answer is yes. Some figures can be folded along a certain line in such a way that all the sides and angles will lay on top of each other. In this case, it is said that the figure has line symmetry.
A figure in the plane has line symmetry if the figure can be mapped onto itself by a reflection in a line. This line of reflection is called the line of symmetry. When a figure has line symmetry, it is said to be reflectionally symmetric or line symmetric.
After learning about line symmetry, Paulina and Heichi decided to study whether some quadrilaterals are line symmetric. To start, they picked a parallelogram.
Without thinking too much, Paulina said it has no line symmetry. However, Heichi said that the parallelogram is symmetric along the line connecting the midpoints of AB and CD. Who is correct?
In the event that ABCD is line symmetric, the lines connecting the midpoints of opposite sides are good candidates of being lines of symmetry. Also, the lines containing the diagonals could work. All possible lines can be tried in the following applet.
As can be seen, no reflection worked! In fact, there is no line along which the parallelogram can be reflected onto itself. This means that ABCD is not line symmetric. In conclusion, Paulina is right.
Despite the previous example showing a parallelogram with no line symmetry, other types of parallelograms should be studied first before making a general conclusion. Consider a rectangle and a rhombus. Study whether or not they are line symmetric.
If both polygons are line symmetric, compare their lines of symmetry.
From the diagram, it can be seen that the rectangle is line symmetric. It has two lines of symmetries, each connecting the midpoints of opposite sides. Next, repeat the same steps with the rhombus.
As can be seen, the rhombus is line symmetric and also has two lines of symmetries. In contrast to the rectangle, however, the lines of symmetries are the lines containing its diagonals.
Before, it was said that rectangles, rhombi, and squares are special kinds of parallelograms because they all have 180^(∘) rotational symmetry. In addition, rectangles and rhombi have line symmetry.
| Polygon | Line Symmetry |
|---|---|
| Rectangles | Along the lines connecting midpoints of opposite sides |
| Rhombi | Along the lines containing the diagonals |
Does a square have line symmetry?
If so, how many different lines of symmetry does it have?
As might be verified, the square is indeed line symmetric. It has four lines of symmetry — two connect the midpoints of opposite sides and two others contain its diagonals.
The line symmetries of a square confirm the claim made previously that squares belong to a particular class of parallelograms.
| Polygon | Number of Line Symmetries | Line Symmetry |
|---|---|---|
| Rectangles | 2 | Along the lines connecting midpoints of opposite sides |
| Rhombi | 2 | Along the lines containing the diagonals |
| Squares | 4 | Two along the lines connecting midpoints of opposite sides and two along the lines containing the diagonals |
Notice that two symmetries of the square correspond to the rectangle's symmetries and the other two correspond to the rhombus symmetries. This suggests that squares are a particular case of rectangles and rhombi.
Paulina and Heichi have the task of investigating whether trapezoids have some symmetry. The teacher gave them the diagram below, but she told them to try any trapezoid they could imagine.
What conclusion should Paulina and Heichi reach?
As investigated, regardless of the dimensions, no trapezoid has rotational symmetry. Next, repeat the same investigation but now checking for line symmetry.
From this last investigation, it may be seen that some trapezoids have line symmetry. Going a bit deeper, it can be concluded that these trapezoids are isosceles trapezoids.
A trapezoid has line symmetry only when it is isosceles trapezoid.
In this case, the line of symmetry is the line passing through the midpoints of each base.
Symmetries are not defined only for two-dimensional figures. The definition can also be extended to three-dimensional figures. In the real world, there are plenty of three-dimensional figures that have some symmetry. For example, sunflowers are rotationally symmetric while butterflies are line symmetric.
A three-dimensional figure is said to have axis symmetry if it can be rotated about a line onto itself by a rotation between 0^(∘) and 360^(∘). This is the equivalent of rotational symmetry.
Examining the diagram, we see that this is an equilateral triangle. This means it has three congruent sides. If we draw a segment from each vertex to the center of the triangle, we create three congruent triangles.
Since the three triangles are congruent, the angles in the center have the same measure. Together, they sum to 360^(∘) which means each of them must have a measure that is one third of this. 360^(∘)/3=120^(∘) Therefore, if we rotate the triangle by 120^(∘), it will map onto itself.
We can also rotate the triangle by 240^(∘) and make it map onto itself. However, this is not represented by the options. The only viable option is D.
This quadrilateral has four congruent sides and four congruent angles. Therefore, this is a square. If we draw segments from each vertex to the center of the square, we create four congruent triangles.
Because the four triangles are congruent, the angles in the center have the same measure. Since they sum to 360^(∘), each of them must be a quarter of this. 360^(∘)/4=90^(∘) This means if we rotate the square by 90^(∘), it will map onto itself.
Also, we can also rotate it by 180^(∘) and make it map onto itself.
Therefore, both C and F are correct.
By drawing segments between the horizontal arrowheads and between the vertical arrowheads, we can see that if we rotate the figure by 90^(∘), it will map onto itself.
Therefore, this figure has a rotational symmetry of 90^(∘).
As in Part A, we will connect each of the star's five edges at the center of the star. This creates 5 congruent angles. Since a full turn is 360^(∘), we can calculate the measure of each congruent angle by dividing 360^(∘) by 5. 360^(∘)/5=72^(∘) Therefore, a 72^(∘) rotation about the center maps the star onto itself.
Let's consider a square because it is a shape with 90^(∘) rotational symmetry. Rotating a square 90^(∘) about its center maps it onto itself.
Rotating it 90^(∘) once more, it maps onto itself again.
Keep in mind that rotating a figure twice by 90^(∘) is the same thing as rotating it by 180^(∘). Therefore, it is impossible for a figure to have 90^(∘) rotational symmetry but not 180^(∘).
Let's consider a rectangle because it has 180^(∘) rotational symmetry. A shape with rotational symmetry of 180^(∘), can be flipped upside down and map onto itself.
Suppose the rectangle has 90^(∘) rotational symmetry, then we would be able to rotate it a quarter of a full turn and have it map onto itself. Try rotating it 90^(∘).
We see that this is not possible because one pair of sides is longer than the other. Therefore, it is possible for a figure to have 180^(∘) rotational symmetry but not 90^(∘).
If we can fold a shape along a line such that the two parts map onto each other, we have found a line of symmetry. For this trapezoid, there is only one way we can fold it that fits this criterion.
As for the cross, we can fold it both horizontally and vertically and have it map onto itself.
However, we can also fold the cross along a 45^(∘) or a - 45^(∘) line and make the figure map onto itself.
For this parallelogram, there is no way of folding it such that the two parts map onto each other. Let's try folding it across a vertical line and see what happens.
Let's also try to fold the parallelogram across a horizontal line.
We could try other lines as well, but the parallelogram cannot be mapped onto itself no matter how we fold it. Therefore, it has no line of symmetry.
One line of symmetry we can see is a vertical line through the middle of the star.
However, we can also draw a line through each of the other four points of the star and fold it such that the star maps onto itself.
We have a total of 5 lines of symmetry.
For any word written using the English alphabet, we have two potential lines of symmetry. Either we fold the top half over the bottom half, or we fold the left half over the right half. Let's try drawing a vertical line of symmetry.
If we fold the left half over the right half, the left part of the U and the M on the left-hand side, will perfectly cover the right part of the U and the M on the right-hand side. Therefore, the word MUM has a vertical line of symmetry. Now let's try to fold the word across a horizontal line of symmetry.
As we can see, the top half does not match the bottom half. Therefore, the word does not have a horizontal line of symmetry. In conclusion, it only has one line of symmetry.
As in Part A, we will try to fold the word along a vertical line of symmetry.
As we can see, the O on the left-hand side and the O right-hand side will map onto each other when the word is folded along the vertical line of symmetry. However, the L and N do not map onto each other. Let's try folding the word across a horizontal line of symmetry.
Again, both O letters will map onto themselves when we fold the top half over the bottom half. However, the upper and lower half of L and N do not map onto each other. Therefore, the word LOON does not have any lines of symmetry.
Let's try folding the word OX horizontally and vertically.
The word OX has one line of symmetry.