To match the solutions with their system, we'll substitute the first point into the first system. If the point is a solution to both equations, it's a solution ot the system.
{y−3x=-6y=-0.5x+8
{4−3⋅8=?-64=?-0.5⋅8+8
{4−24=?-64=?-4+8
{-20=-64=4
The equality is true for the second equation but not for the first one. A solution to a system of equations has to satisfy
all equations. Therefore,
(8,4) cannot be a solution to the first system. Let's try the second point,
(4,6).
{y−3x=-6y=-0.5x+8
{6−3⋅4=?-66=?-0.5⋅4+8
{6−12=?-66=?-2+8
{-6=-66=6
Both equations are satisfied for
(4,6). Thus, it's a solution to the system. Continue with B and check with the first point.
{y−20=-2xy−x+4=0(I)(II)
{4−20=?-2⋅84−8+4=?0
{4−20=?-164−8+4=?0
{-16=-160=0
It's a solution! This means that the last point must be a solution to the last system of equations. Let's find out.
{y=2−5x7x−10=y(I)(II)
{-3=?2−5⋅17⋅1−10=?-3
{-3=?2−57−10=?-3
{-3=-3-3=-3
We have now paired the three solutions with the three systems.
A:B:C: (4,6) (8,4) (1,-3)