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| 12 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
In the graph below, four lines and their corresponding linear equations can be seen on a coordinate plane. Determine which lines intersect at one point, which lines intersect at infinitely many points, and which lines do not intersect at all.
Consider the definition of equations in two variables.
(I): LHS/2=RHS/2
(I): Write as a sum of fractions
(I): ca⋅b=ca⋅b
(I): Put minus sign in front of fraction
(I): Calculate quotient
(I): Identity Property of Multiplication
Now that the equations are both written in slope-intercept form, they can be graphed on the same coordinate plane.
The point where the lines intersect is the solution to the system.
The lines appear to intersect at (1.5,2.5). Therefore, this is the solution to the system — the value of x is 1.5 and the value of y is 2.5.
Mark is throwing a party, so he bought some donuts and lollipops for his friends.
Start by writing both linear equations in slope-intercept form.
(I): LHS−x=RHS−x
(II): LHS−3x=RHS−3x
(II): LHS/2=RHS/2
(II): Write as a sum of fractions
(II): ca⋅b=ca⋅b
(II): Put minus sign in front of fraction
(II): Calculate quotient
Since the number of items cannot be negative, only the first quadrant will be considered for the graph. The y-intercept of the second equation is 26, so the first point on that line is (0,26). The slope is -1.5. To better match the scale of this graph, the second point can be plotted by going 4 steps to the right and 4⋅1.5=6 steps down.
Finally, the point of intersection P can be identified.
The point of intersection of the lines is P(12,8). In the context of the situation, this means that Mark bought x=12 donuts and y=8 lollipops.
Consider the graph of a system of equations consisting of two lines. What is the solution to the system?
When a system of linear equations has two equations and two variables, the system can have zero, one, or infinitely many solutions.
If a system has no solution, its graph might look similar to this one.
If a system of equations has one solution, its graph consists of two lines that intersect exactly once. The point of intersection is the solution to the system.
If a system of equations has infinitely many solutions, the lines intersect at infinitely many points. This means the lines lie on top of each other or coincide with each other.
These lines are said to be coincidental, and since they have the same slope and y-intercept, they are different versions of the same line. Here is one example of a system that has an infinite number of solutions.
First, rewrite the equations into slope-intercept form. Then, graph the equations and find the point of intersection of the lines.
(I): LHS−8q=RHS−8q
(I): LHS/5=RHS/5
(II): Commutative Property of Addition
(II): LHS/12.5=RHS/12.5
(I), (II): Put minus sign in front of fraction
(I), (II): ca⋅b=ca⋅b
(I), (II): Calculate quotient
The lines overlap each other. They intersect at infinitely many points, which means that the system of equations has infinitely many solutions. This indicates that the system of equations was not set up properly. Maybe the same information was written in two different ways, which resulted in two equations that represent the same line.
Begin by rewriting the equations into slope-intercept form. Then, graph both equations on the same coordinate plane using their slopes and y-intercepts.
(I): LHS−9a=RHS−9a
(II): Commutative Property of Addition
(I): LHS/4=RHS/4
(II): LHS/2=RHS/2
(I), (II): Write as a sum
(I), (II): Put minus sign in front of fraction
(I), (II): Calculate quotient
Consider the given system of equations. Does it have zero, one, or infinitely many solutions?
Characteristics | Number of Solutions |
---|---|
Same slope and same y-intercept | Infinitely many solutions |
Same slope and different y-intercepts | No solution |
Different slopes | One solution |
An alternative method for determining the number of solutions to a system of equations is to compare the slopes and y-intercepts of the equations. y= mx+ b We can use the slope-intercept form of each equation, where m is the slope and the point (0, b) is the y-intercept, to help us with this. There are three possibilities when comparing two linear equations in a system.
Slope | y-intercept | Graph Description | Number of Solutions |
---|---|---|---|
m_1≠ m_2 | Irrelevant | Intersecting lines | One solution |
m_1=m_2 | b_1≠ b_2 | Parallel lines | No solution |
m_1=m_2 | b_1=b_2 | Same line | Infinitely many |
Let's rewrite the equations in the given system in slope-intercept form, highlighting the m and b values.
Given Equation | Slope-Intercept Form | Slope m | y-intercept b |
---|---|---|---|
3x-2y=-1/2 | y= 3/2x+ 1/4 | 3/2 | (0, 1/4) |
6x-4y=- 1 | y= 3/2x+ 1/4 | 3/2 | (0, 1/4) |
From the table, we can see that the slopes of the lines are equal, so the lines are either parallel or are the same line. Looking at the y-intercepts, we can tell the lines are the same because the point at which each line crosses the y-axis is the same. Therefore, the system has infinitely many solutions.
A cell phone provider FractionTalk offers a plan Chit Chat
that costs $30 per month plus $0.25 per text message sent or received. A comparable plan Textopia
costs $55 per month but offers unlimited text messaging.
Let's start by writing a system of equations for the situation. Let t be the number of text messages Zain sends or receives and c be the total cost of the plan. t &= number of text messages c &= cost of the plan For the Chit Chat plan, Zain has to pay $ 30 per month plus $ 0.25 for each text message sent or received, so 0.25 t. Let's use this information to write an equation for the total cost of this plan. Chit Chat c= 30+ 0.25 t The second plan, Textopia, costs $ 55 per month, regardless of the number of messages sent or received. Let's write an equation for this plan. Textopia c= 55 Together these equations form a system of equations. c= 30+ 0.25 t c= 55 Let's graph the system to find its solution. We can graph the first equation by plotting the y-intercept at (0,30) and then using the slope of 0.25 to move 1* 40=40 units right and 0.25*40=10 units up. We can graph the second equation as a horizontal line intersecting the y-axis at (0,55).
Now we can identify the coordinates of the point of intersection of the lines.
We can see that the graphs intersect at the point (100,55). Since t represents the number of text messages, this tells us that Zain would have to send or receive 100 text messages for the plans to cost the same each month.
We can decide which plan is better for sending or receiving only 60 messages per month by analyzing the graph we created in Part A. Since the horizontal line is constant at y=55, we only need to analyze the graph of the first plan Chit Chat.
We can see that for the first cell phone plan, Zain would only pay about $45 per month, which is less than the $55 for the Textopia plan. Therefore, it is more logical for Zain to buy the first plan.
Ali, Davontay, and Diego love solving math challenges together, so they decided to form the Code Crunchers Club. They plan split any rewards for completing puzzles equally among themselves.
We are given two equations that we can use to form a system of equations. 3x+5y=24 12x+20y=82 Let's graph the system to find its solution. First, we need to rewrite the equations from standard form into slope-intercept form. Standard Form Ax+By=C ⇓ Slope-Intercept Form y=mx+b Let's do it!
3x+5y=24 | 12x+20y=82 | |
---|---|---|
Move x-term | 5y=- 3x+24 | 20y=- 12x+82 |
Divide to isolate y | y=- 3/5x+24/5 | y=- 12/20x+82/20 |
Calculate | y=- 0.6x+4.8 | y=- 0.6x+4.1 |
Slope | m=- 0.6 | m=- 0.6 |
Y-intercept | b=4.8 | b=4.1 |
Next, we graph the first equation by plotting the y-intercept at (0,4.8) and then using the slope of - 0.6 to move 1* 3=3 units right and 0.6* 3=1.8 units down. We will then draw a line through the two points. After that, we will follow the same procedure to graph the second line.
We can see that the lines do not intersect and are parallel to each other. This means that the system of equations has no solution. Ali must have made a mistake in his clues!
Dominika sells small and large handmade candles at a craft fair. She collects $228 after selling a total of 32 candles. She sells a small candle for $6 and a large candle for $8.
We know that Dominika sold a total of 32 candles. If we let s be the number of small candles sold and l be the number of large candles sold, we can write an equation to represent the total number of candles sold. s+ l=32 Let's rearrange this equation to isolate the l-variable to make it easier to use this equation later. l=- s+32 We also know that a large candle sells for $8 and a small candle for $6. Let's use this information to express how much money Dominika collected in terms of s and l.
Verbal expression | Algebraic expression |
---|---|
Price per large candle | 8 |
Number of large candles sold | l |
Money collected from selling large candles | 8 l |
Price per small candle | 6 |
Number of small candles sold | s |
Money collected from selling small candles | 6 s |
Total amount of money collected | 8 l+ 6 s |
Since Dominika collected $ 228, let's write an equation to relate the total amount of money earned with the number of the candles sold. 8 l+ 6 s=228 Now we will rearrange this equation by isolating l since it will help us graph the equation. In other words, we will rewrite the equation in slope-intercept form.
Now that we have both equations in slope-intercept form, we can plot them using their y-intercepts and slopes and then find the point of intersection.
From the graph, we can see that the solution seems to be (14,18). We can also check this solution by substituting it into the equations. Let's start with the first one.
Now let's check the second one.
Since both equations resulted in a true statment, the point (14,18) is the solution to the system. This means that Dominika sold 14 small candles and 18 large candles.