5. Solving System of Equations Graphically
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Chapter 7
5.
Solving System of Equations Graphically
This lesson explains how to solve systems of linear equations by graphing. It shows how the intersection of two lines on a graph represents the solution to the system, whether it is one unique solution, no solution, or infinitely many solutions. This method is helpful for visualizing relationships between equations and understanding their solutions.
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| | 12 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Solving System of Equations Graphically
Slide of 12
Some real-life situations can be modeled with more than one equation that can be joined into a system of equations. There are different methods of solving systems of equations. This lesson will focus on one of them, which involves graphing the equations.
Catch-Up and Review
Here are a few recommended readings before getting started with this lesson.
Explore
Lines on the Same Plane
In the graph below, four lines and their corresponding linear equations can be seen on a coordinate plane. Determine which lines intersect at one point, which lines intersect at infinitely many points, and which lines do not intersect at all.
Discussion
Introducing Systems of Equations
Consider the definition of equations in two variables.
Concept
Equation In Two Variables
An equation in two variables is a mathematical relation between two equal quantities that involves two variables.
Solving an equation in two variables results in an ordered pair that makes the equation true.
Discussion
Systems of Equations
A system of equations is a set of two or more equations involving the same variables. The solutions to a system of equations are values for these variables that satisfy all the equations simultaneously. A system of equations is usually written as a vertical list with a curly bracket on the left-hand side.
Systems of equations can be solved graphically or algebraically.
{2x−3y=13x+y=7
Graphically, solutions to systems of equations are the points where the graphs of the equations intersect. For this reason, these solutions are usually expressed as coordinates. Discussion
Solving a System of Linear Equations Graphically
Solving a system of linear equations graphically means graphing the lines represented by the equations of the system and identifying the point of intersection. Consider an example system of equations.
Sometimes the point of intersection of the lines is not a lattice point. In this case, the solution found by solving the system of equations graphically is approximate.
{2y=-2x+8x=y−1
To solve the system of equations, three steps must be followed.
1
Write the Equations in Slope-Intercept Form
expand_more Start by writing the equations in slope-intercept form by isolating the y-variables. For the first linear equation, divide both sides by 2. For the second equation, add 1 to both sides.
{2y=-2x+8x=y−1(I)(II)
▼
(I): Solve for y
DivEqn
(I): LHS/2=RHS/2
{y=2-2x+8x=y−1
WriteSumFrac
(I): Write as a sum of fractions
{y=2-2x+28x=y−1
MovePartNumRight
(I): ca⋅b=ca⋅b
{y=2-2x+28x=y−1
MoveNegNumToFrac
(I): Put minus sign in front of fraction
{y=-22x+28x=y−1
CalcQuot
(I): Calculate quotient
{y=-1x+4x=y−1
IdPropMult
(I): Identity Property of Multiplication
{y=-x+4x=y−1
▼
(II): Solve for y
{y=-x+4y=x+1
2
Graph the Lines
expand_more Now that the equations are both written in slope-intercept form, they can be graphed on the same coordinate plane.
3
Identify the Point of Intersection
expand_more The point where the lines intersect is the solution to the system.
The lines appear to intersect at (1.5,2.5). Therefore, this is the solution to the system — the value of x is 1.5 and the value of y is 2.5.
Example
Modeling With a System of Linear Equations
Mark is throwing a party, so he bought some donuts and lollipops for his friends.
{x+y=203x+2y=52
Solve the system by graphing and find how many donuts and lollipops he bought. {"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><\/span><\/span>"},"formTextBefore":"Donuts <span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:1em;vertical-align:-0.25em;\"><\/span><span class=\"mopen\">(<\/span><span class=\"mord mathdefault\">x<\/span><span class=\"mclose\">)<\/span><\/span><\/span><\/span>:","formTextAfter":null,"answer":{"text":["12"]}}
{"type":"text","form":{"type":"math","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><\/span><\/span>"},"formTextBefore":"Lollipops <span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:1em;vertical-align:-0.25em;\"><\/span><span class=\"mopen\">(<\/span><span class=\"mord mathdefault\" style=\"margin-right:0.03588em;\">y<\/span><span class=\"mclose\">)<\/span><\/span><\/span><\/span>:","formTextAfter":null,"answer":{"text":["8"]}}
Hint
Start by writing both linear equations in slope-intercept form.
Solution
To start, each equation in the system will be rewritten in slope-intercept form. This means that the y-variable will be isolated in both equations.
Now, the slope and the y-intercept of each line will be used to draw the graphs on the same coordinate plane. The y-intercept of the first equation is 20, so the first point is (0,20). The slope is -1, so the second point can be plotted by 1 step to the right and 1 step down on the graph. Since this graph uses a different scale, try moving 4 steps right and 4 steps down instead. 
{x+y=203x+2y=52(I)(II)
▼
(I), (II): Write in slope-intercept form
SubEqn
(I): LHS−x=RHS−x
{y=-x+203x+2y=52
SubEqn
(II): LHS−3x=RHS−3x
{y=-x+202y=-3x+52
DivEqn
(II): LHS/2=RHS/2
{y=-x+20y=2-3x+52
WriteSumFrac
(II): Write as a sum of fractions
{y=-x+20y=2-3x+252
MovePartNumRight
(II): ca⋅b=ca⋅b
{y=-x+20y=2-3x+252
MoveNegNumToFrac
(II): Put minus sign in front of fraction
{y=-x+20y=-23x+252
CalcQuot
(II): Calculate quotient
{y=-x+20y=-1.5x+26
Since the number of items cannot be negative, only the first quadrant will be considered for the graph. The y-intercept of the second equation is 26, so the first point on that line is (0,26). The slope is -1.5. To better match the scale of this graph, the second point can be plotted by going 4 steps to the right and 4⋅1.5=6 steps down.
Finally, the point of intersection P can be identified.
The point of intersection of the lines is P(12,8). In the context of the situation, this means that Mark bought x=12 donuts and y=8 lollipops.
Pop Quiz
Finding the Solution to a System of Equations
Consider the graph of a system of equations consisting of two lines. What is the solution to the system?
Discussion
Number of Solutions to a System of Linear Equations
When a system of linear equations has two equations and two variables, the system can have zero, one, or infinitely many solutions.
No Solution
If a system has no solution, its graph might look similar to this one.
{y=3x+2y=3x−5
One Solution
If a system of equations has one solution, its graph consists of two lines that intersect exactly once. The point of intersection is the solution to the system.
{y=-x+5y=3x−2
Infinite Number of Solutions
If a system of equations has infinitely many solutions, the lines intersect at infinitely many points. This means the lines lie on top of each other or coincide with each other.
These lines are said to be coincidental, and since they have the same slope and y-intercept, they are different versions of the same line. Here is one example of a system that has an infinite number of solutions.
{y=3x+12y=6x+2
Example
Determining the Numbers of Tasks and Questions in Balloons
To start the party, Mark suggested they play a fun game. He invited everyone to a room full of balloons. Each balloon had a note with a task to complete or a question to answer.
The number of tasks t and questions q can be determined by the following system of equations.
{5t+8q=11612.5t=290−20q
Solve the system of equations by graphing. {"type":"text","form":{"type":"equation","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":"","description":[{"id":0,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.61508em;vertical-align:0em;\"><\/span><span class=\"mord mathdefault\">t<\/span><\/span><\/span><\/span>"},{"id":1,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.625em;vertical-align:-0.19444em;\"><\/span><span class=\"mord mathdefault\" style=\"margin-right:0.03588em;\">q<\/span><\/span><\/span><\/span>"}]},"formTextBefore":null,"formTextAfter":null,"answer":{"text":[{"id":0,"text":""},{"id":1,"text":""}],"noSolution":false,"infiniteSolution":true}}
Hint
First, rewrite the equations into slope-intercept form. Then, graph the equations and find the point of intersection of the lines.
Solution
To solve the system of equations graphically, both equations should be rewritten in slope-intercept form first. Let q be the independent variable and t be the dependent variable.
Notice that both equations simplify to the same equation. This equation can be graphed by using its slope and its y-intercept. 
{5t+8q=11612.5t=290−20q(I)(II)
▼
(I), (II): Write in slope-intercept form
SubEqn
(I): LHS−8q=RHS−8q
{5t=-8q+11612.5t=290−20q
DivEqn
(I): LHS/5=RHS/5
{t=5-8q+511612.5t=290−20q
CommutativePropAdd
(II): Commutative Property of Addition
{t=5-8q+511612.5t=-20q+290
DivEqn
(II): LHS/12.5=RHS/12.5
{t=5-8q+5116t=12.5-20q+12.5290
(I), (II): Put minus sign in front of fraction
{t=-58q+5116t=-12.520q+12.5290
(I), (II): ca⋅b=ca⋅b
{t=-58q+5116t=-12.520q+12.5290
(I), (II): Calculate quotient
{t=-1.6q+23.2t=-1.6q+23.2
The lines overlap each other. They intersect at infinitely many points, which means that the system of equations has infinitely many solutions. This indicates that the system of equations was not set up properly. Maybe the same information was written in two different ways, which resulted in two equations that represent the same line.
Example
Scavenger Hunt
Later in the evening, Mark suggested doing a scavenger hunt. All the hunters were split into two teams. The team that found the most items would win.
Team 1, the Adventure Seekers, found a items. Team 2, the Mystery Solvers, found m items. Mark’s parents tallied up the scores and, to make it more of a challenge, decided to give the scores as a system of equations. Whoever solves the system will get an extra gift!
External credits: @upklyak
{9a+4m=542m=34−4.5a
Solve the system using the graphing method to find how many items each team found. {"type":"text","form":{"type":"equation","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":"","description":[{"id":0,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.43056em;vertical-align:0em;\"><\/span><span class=\"mord mathdefault\">a<\/span><\/span><\/span><\/span>"},{"id":1,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.43056em;vertical-align:0em;\"><\/span><span class=\"mord mathdefault\">m<\/span><\/span><\/span><\/span>"}]},"formTextBefore":null,"formTextAfter":null,"answer":{"text":[{"id":0,"text":""},{"id":1,"text":""}],"noSolution":true,"infiniteSolution":false}}
Hint
Begin by rewriting the equations into slope-intercept form. Then, graph both equations on the same coordinate plane using their slopes and y-intercepts.
Solution
The given system of equations needs to be solved graphically.
Notice that the equations have the same slope of -2.25 but different y-intercepts. This means that the lines are parallel. Graph them using the slope and the y-intercepts.
Recall the the solution to the system of equations is the point of intersection of the lines. However, since the lines are parallel, they never intersect. Therefore, there is no solution to the system of equations. Since Mark's parents are not mathematicians, they probably made a mistake, so their system did not work.
{9a+4m=542m=34−4.5a
To do so, both equations should be rewritten in slope-intercept form first. Let a be the independent variable and m be the dependent variable.
{9a+4m=542m=34−4.5a(I)(II)
▼
(I), (II): Write in slope-intercept form
SubEqn
(I): LHS−9a=RHS−9a
{4m=-9a+542m=34−4.5a
CommutativePropAdd
(II): Commutative Property of Addition
{4m=-9a+542m=-4.5a+34
DivEqn
(I): LHS/4=RHS/4
{m=4-9a+542m=-4.5a+34
DivEqn
(II): LHS/2=RHS/2
{m=4-9a+54m=2-4.5a+34
(I), (II): Write as a sum
{m=4-9a+454m=2-4.5a+234
(I), (II): Put minus sign in front of fraction
{m=-49a+454m=-24.5a+234
(I), (II): Calculate quotient
{m=-2.25a+13.5m=-2.25a+17
Pop Quiz
Determining the Number of Solutions to a System of Equations
Consider the given system of equations. Does it have zero, one, or infinitely many solutions?
Closure
Identifying the Number of Solutions From Slope-Intercept Form
This lesson focused on solving systems of linear equations by graphing. When equations in the system are written in standard or point-slope form, it is unclear how many solutions the system has. However, the situation is different when it comes to slope-intercept form.
These facts can be useful when solving systems of equations.
Slope-Intercept Formy=mx+b
If both equations of the system of equations are in slope-intercept form, there is no need to graph them in order to find the number of solutions. It can be found by analyzing the slopes and y-intercepts of the equations. | Characteristics | Number of Solutions |
|---|---|
| Same slope and same y-intercept | Infinitely many solutions |
| Same slope and different y-intercepts | No solution |
| Different slopes | One solution |
Solving System of Equations Graphically
Exercises
The following graph corresponds to the system of equations next to it.
{"type":"text","form":{"type":"point2d","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false,"decimal":false,"function":false},"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><\/span><\/span>"},"formTextBefore":null,"formTextAfter":null,"answer":{"text1":"4","text2":"3"}}
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The solution of the system of linear equations is the point where the graphs of the equations intersect.
From the graph, we can tell that this point is (4,3). Let's check this solution by substituting the point into both equations.
Since both equations hold true after substituting the values of the point, we know that (4,3) is the solution of the system of equations.
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The following graph corresponds to the system of equations next to it.
{"type":"text","form":{"type":"point2d","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false,"decimal":false,"function":false},"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><\/span><\/span>"},"formTextBefore":null,"formTextAfter":null,"answer":{"text1":"-5","text2":"2"}}
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The solution of the system of linear equations is the point where the graphs of the equations intersect.
From the graph, we can tell that this point is (- 5,2). Let's check this solution by substituting the point into both equations.
Since both equations are true after substituting the values of the point, we know that (- 5,2) is indeed the solution of the system of equations.
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Solve the system of equations by graphing.
{5x−5y=20y=-4
{"type":"text","form":{"type":"equation","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":"","description":[{"id":0,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.43056em;vertical-align:0em;\"><\/span><span class=\"mord mathdefault\">x<\/span><\/span><\/span><\/span>"},{"id":1,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.625em;vertical-align:-0.19444em;\"><\/span><span class=\"mord mathdefault\" style=\"margin-right:0.03588em;\">y<\/span><\/span><\/span><\/span>"}]},"formTextBefore":null,"formTextAfter":null,"answer":{"text":[{"id":0,"text":"0"},{"id":1,"text":"-4"}],"noSolution":false,"infiniteSolution":false}}
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We can determine the solution to the system by graphing the given equations. This will be the point at which the lines intersect. To do this, we will need the equations to be in slope-intercept form to help us identify the slope m and y-intercept b.
Write the Equations in Slope-Intercept Form
Let's rewrite each of the equations in the system in slope-intercept form, highlighting the m and b values.
| Given Equation | Slope-Intercept Form | Slope m | y-intercept b |
|---|---|---|---|
| 5x-5y=20 | y= 1x+( - 4) | 1 | (0, - 4) |
| y=- 4 | y= 0x+( - 4) | 0 | (0, - 4) |
Graphing the System
We will start graphing the equations by plotting the y-intercepts. From there, we will use the slope of each equation to determine another point on the line and connect the points with a line.
We can see that the lines intersect at exactly one point.
The point of intersection at (0,- 4) is the solution to the system.
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Solve the system of equations by graphing.
{y=32x+4y=31x+1
{"type":"text","form":{"type":"equation","options":{"comparison":"1","nofractofloat":false,"keypad":{"simple":true,"useShortLog":false,"variables":[],"constants":[]},"rendered":false},"text":"","description":[{"id":0,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.43056em;vertical-align:0em;\"><\/span><span class=\"mord mathdefault\">x<\/span><\/span><\/span><\/span>"},{"id":1,"text":"<span class=\"katex\"><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"strut\" style=\"height:0.625em;vertical-align:-0.19444em;\"><\/span><span class=\"mord mathdefault\" style=\"margin-right:0.03588em;\">y<\/span><\/span><\/span><\/span>"}]},"formTextBefore":null,"formTextAfter":null,"answer":{"text":[{"id":0,"text":"-9"},{"id":1,"text":"-2"}],"noSolution":false,"infiniteSolution":false}}
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We can determine the solution to the system by graphing the given equations. This will be the point at which the lines intersect. Since both equations area already given in slope-intercept form, let's analyze them to identify the slope m and y-intercept b in each equation.
| Given Equation | Slope-Intercept Form | Slope m | y-intercept b |
|---|---|---|---|
| y=2/3x+4 | y= 2/3x+ 4 | 2/3 | (0, 4) |
| y=1/3x+1 | y= 1/3x+ 1 | 1/3 | (0, 1) |
Next, let's graph the equations. We will start by plotting the y-intercepts, then use the slope to determine another point that satisfies the equation. Then we can connect the points with a line.
We can see that the lines intersect at exactly one point.
The point of intersection at (- 9,- 2) is the solution to the system.
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Solve the system by graphing. Determine whether the system has one solution, no solution, or infinitely many solutions.
{y−1.5x=64y=6x+24
{"type":"choice","form":{"alts":["One solution","No solution","Infinitely many solutions"],"noSort":true},"formTextBefore":"","formTextAfter":"","answer":2}
{6x−2y=42y=-21x+25
{"type":"choice","form":{"alts":["One solution","No solution","Infinitely many solutions"],"noSort":true},"formTextBefore":"","formTextAfter":"","answer":0}
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We can determine the number of solutions to the system by graphing the given equations. This will be the point at which the lines intersect. To do this, we need the equations to be in slope-intercept form to help us identify the slope colIVm and y-intercept b.
Write in Slope-Intercept Form
Let's rewrite each of the equations in the system in slope-intercept form, highlighting the m and b values.
| Given Equation | Slope-Intercept Form | Slope m | y-intercept b |
|---|---|---|---|
| y-1.5x=6 | y= 1.5x+ 6 | 1.5 | (0, 6) |
| 4y=6x+24 | y= 1.5x+ 6 | 1.5 | (0, 6) |
When converted into slope-intercept form, we can see that these two equations are actually the same. This means that there are infinitely many solutions. Let's confirm this by graphing the system.
Graphing the System
To graph these equations, we will start by plotting the y-intercepts, then use the slope to determine another point that satisfies the equation. Then we can connect the points with a line.
The equations overlap at every possible point. Since the equations overlap, they also intersect
at every point along the line. Therefore, the system has infinitely many solutions.
We can determine the number of solutions to the system by graphing the given equations. This will be the point at which the lines intersect. To do this, we need the equations to be in slope-intercept form to help us identify the slope m and y-intercept b.
Write in Slope-Intercept Form
Let's rewrite each of the equations in the system in slope-intercept form, highlighting the m and b values.
| Given Equation | Slope-Intercept Form | Slope m | y-intercept b |
|---|---|---|---|
| 6x-2y=4 | y= 3x+( - 2) | 3 | (0, - 2) |
| 2y=- 1/2x+5/2 | y= -1/4x+ 5/4 | -1/4 | (0, 5/4) |
Graphing the System
To graph these equations, we will start by plotting the y-intercepts, then use the slope to determine another point that satisfies the equation. Then we can connect the points with a line.
We can see that the lines intersect at exactly one point.
The point of intersection at (1,1) is the one solution to the system.
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Solving System of Equations Graphically
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