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| 17 Theory slides |
| 11 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here is a recommended reading before getting started with this lesson.
In a nonproportional relationship, the line passes through the point (0,b), or the y-intercept. Use the Slope Formula to derive the equation for a nonproportional relationship. m=y_2-y_1/x_2-x_1
Assume that the other point the line passes through is (x,y).The intercepts of a line provide information about the position of the line in the coordinate plane. They can be used to identify the equation of a line from known points or to graph a line from its equation.
The applet shows the graphs of different lines. Identify the intercepts of these lines.
A linear equation is an equation with at least one linear term and any number of constants. No other types of terms may be included. Linear equations in one variable have the following form, where a and b are real numbers and a≠ 0.
ax+b=0 or ax = b
Linear equations in two variables have the form below, where a, b, and c are real numbers and a≠ 0 and b≠ 0.
ax+by+c=0 or ax+by = c
A linear equation can be written in the following form called the slope-intercept form.
y=mx+b
In this form, m is the slope and b is the y-intercept. These are the general characteristics or parameters of the line. They determine the steepness and the position of the line on the coordinate plane. Consider the following graph.
This line has a slope of 2 and a y-intercept of 1. The equation of the line can be written in slope-intercept form using these values.
y= mx+ b ⇓ y= 2x+ 1The following applet generates linear equations. Those equations represent the relation between two variables x and y. Determine whether the generated equation is in slope-intercept form.
The y-intercept b can be used to find the the first point the line passes through. y=2x-3 ⇔ y= 2x+( - 3) The y-intercept b is - 3. Plot the point (0, - 3) on a coordinate plane.
There should be at least two points to draw a line. The second point can be plotted on the coordinate plane by using the slope m. Based on the equation, the slope is 2. y= 2x+( - 3) This means that the rise is 2 and the run is 1. m=rise/run ⇔ 2=2/1 From the first point (0,- 3), move 1 unit right and 2 units up to plot the second point.
Jordan is investigating the fish population in Grassy Lake. The number of fish in the lake was counted as 60 in 2016.
She finds out that the population increases by 120 after each year. The following equation represents the fish population in the lake. y=120x+60 In this equation, y is the number of fish in the lake after x years.
y-intercept: Number of fish in the year 2016
y= mx+ b ⇓ y= 120x+ 60 The slope is 120 and the y-intercept is 60. This means that the line crosses the y-axis at (0, 60).
Next, move 1 unit to the right and 120 units up from the y-intercept to plot another point.
Finally, the graph of the equation can be competed by drawing a line passing through these two points.
Note that the number of years passed or the number of fish cannot be negative. Therefore, only the first quadrant of the coordinate plane is shown.
Slope &= 120 y-intercept &= 60 In this context, the slope 120 represents the increase in the fish population per year. The y-intercept 60 represents the number of fish in 2016.
The y-intercept b and the slope m of a line must be found to write the equation of the graph of the line in slope-intercept form . y=mx+b Consider the line shown as an example.
The y-intercept is the y-coordinate of the point where the line crosses the y-axis. This line intercepts the y-axis at (0,- 4), which means that the y-intercept is - 4.
The y-intercept can be substituted into the slope-intercept form equation for b. y=mx+ b ⇓ y=mx - 4
Next, the slope of the line must be determined. The slope of a line is the ratio of the rise and run of the line. m=rise/run The rise is the vertical distance between two points and the run is the horizontal distance. Any two points on the line can be used to find the slope.
For this line, the rise is 6 and the run is 2. Substitute these values into the formula to calculate the slope of the line. m=6/2 ⇒ m=3
Finally, substitute m= 3 in to the equation from Step 2 to complete the equation. y= mx-4 ⇓ y= 3x-4 The equation of the line in slope-intercept form is now complete.
Jordan turns her attention to the cheetah population over years.
She finds a graph on the Internet that shows the number of cheetahs over years since 1900.
Jordan wants to represent the graph algebraically to interpret it further.
y-intercept: Number of cheetahs in the year 1900
y= mx+ b In this form, m is the slope and b is the y-intercept. The y-intercept of a line is the y-coordinate of the point where the line crosses the y-axis.
In the given graph, the line intercepts the y-axis at (0,100 000). This means that the y-intercept of the line is 100 000. Substitute 100 000 for b into the slope-intercept form of an equation. y= mx+ b ⇓ y= mx+ 100 000 The slope of a line is the ratio of the rise and run of the line. m=rise/run Any two points on the line can be chosen to determine the rise and run. One point can be the one where the line intercepts the y-axis. The other point can be (50,60 000) for simplicity.
rise= -40 000, run= 50
Put minus sign in front of fraction
Calculate quotient
y= -800x+ 100 000 The slope of the line is negative, which suggests that the number of cheetahs decreases by 800 per year. The y-intercept represents that there were 100 000 cheetahs in 1900.
y= 0
LHS+800x=RHS+800x
.LHS /800.=.RHS /800.
Calculate quotient
The slope m and the y-intercept b of a line must be known to write a linear equation in slope-intercept form. y=mx+b When only two points on the line are known, the following four-step method can be used. For example, the equation of the line that passes through the points (- 4,1) and (8,4) will be written.
Substitute ( - 4, 1) & ( 8,4)
a-(- b)=a+b
Add and subtract terms
Calculate quotient
Now that the value of the slope is known, it can be substituted for m in the slope-intercept form of an equation. y= mx+b ⇓ y= 0.25x+b
x= 8, y= 4
Multiply
LHS-2=RHS-2
Rearrange equation
Lastly, the complete equation in slope-intercept form can be written by substituting the y-intercept into the equation from Step 2. y=0.25x+ b ⇓ y=0.25x+ 2 The equation of the line in slope-intercept form is now complete.
Jordan is interested in endangered animals. She reads a magazine to learn what can be done to save these animals.
Suppose Jordan reads the same number of pages each day. The following table shows the number of pages y left in the magazine after x days.
Number of Days x | 5 | 9 | 15 |
---|---|---|---|
Number of Pages y | 147 | 95 | 17 |
Write an equation for the given situation in slope-intercept form using the Slope Formula.
The given equations are in slope-intercept form. y= mx+ b In this form, m is the slope and b is the y-intercept. These two characteristics need to be determined to write an equation in slope-intercept form. Begin by representing given information in terms of points (x,y).
Number of Days x | 5 | 9 | 15 |
---|---|---|---|
Number of Pages y | 147 | 95 | 17 |
Point (x,y) | ( 5, 147) | ( 9, 95) | ( 15, 17) |
Substitute ( 5, 147) & ( 9, 95)
Subtract terms
Put minus sign in front of fraction
Calculate quotient
x= 15, y= 17
(- a)b = - ab
LHS+195=RHS+195
Rearrange equation
Write an equation in slope-intercept form using the given line, two points, or equation.
Determine the slope or y-intercept the given line based on its graph, points, or its equation. Be careful — the equation may or may not be written in slope-intercept form!
Substitute ( 0, b) & ( x, y)
Subtract term
LHS * x=RHS* x
a/x* x = a
LHS+b=RHS+b
Rearrange equation
The table below shows the relation between degrees Celsius and degrees Fahrenheit.
^(∘) C | -20 | -10 | 0 | 5 | 15 |
---|---|---|---|---|---|
^(∘) F | -4 | 14 | 32 | 41 | 59 |
We want to write an equation in slope-intercept form for the given table. y= mx+ b In this form, m is the slope and b is the y-intercept. Let x represent the degrees Celsius and y represent the degrees Fahrenheit. We can now choose any two ordered pairs from the table to find the slope of the equation.
^(∘) C | -20 | -10 | 0 | 5 | 15 |
---|---|---|---|---|---|
^(∘) F | -4 | 14 | 32 | 41 | 59 |
Let's use ( 5, 41) and ( 15, 59). We can substitute these points into the slope formula and simplify to find the slope of the line. Let's do it!
The slope of the equation is 95. Next, we will find the y-intercept of the equation. To make this easier, let's find an ordered pair with an x-coordinate 0.
^(∘) C | -20 | -10 | 0 | 5 | 15 |
---|---|---|---|---|---|
^(∘) F | -4 | 14 | 32 | 41 | 59 |
The line of the equation intercepts the y-axis at (0,32). Therefore, the y-intercept is 32. Let's substitute the values of the slope and y-intercept into the slope-intercept form to write our equation. y= mx+ b ⇒ y= 9/5x+ 32 The equation in slope-intercept form that represents the values in the table is y= 95x+32.
Jordan says the equation of the line given below is y= 13x-2. Tadeo says that the equation of the line is y=- 13x+2.
We want to decide who is correct about the equation of the given line. Notice that both equations are in slope-intercept form. Jordan:& y= 1/3x-2 ⇔ y= 1/3x+( -2) [0.8em] Tadeo:& y=-1/3x+2 ⇔ y= -1/3x+ 2 Let's also write an equation of the line in slope-intercept form. We will first find the slope of the line. We can choose two points on the line, then use them to determine the rise and run.
The rise is 1 and the run is 3. Remember, the slope is the ratio of the rise to the run. m=rise/run ⇒ m=1/3 The slope of the line is 13. We can also see that the line intercepts the y-axis at (0,-2). This means that the y-intercept is -2. Let's substitute these values in slope-intercept form. y= mx+ b ⇓ y= 1/3x+( -2) The equation of the line is y= 13x-2. This means that Jordan is correct!
A taxi fare can be determined by the following equation. y=0.5x + 3 In this equation, x is the number of miles traveled and y is the total charge in dollars. Graph the equation. What do the slope and the y-intercept represent in this context?
We want to graph and interpret the slope and the y-intercept of the following equation. y=0.5x + 3 We can see that the equation is written in slope-intercept form, so let's begin by identifying its slope and y-intercept. y= 0.5x + 3 The slope is 0.5 and the y-intercept is 3. This means that the line of this equation intercepts the y-axis at (0,3). Let's plot this point on the coordinate plane.
We need a second point to graph the line. We already identified that the slope of the line is 0.5, but we can convert this decimal to a fraction to make it easier to use to find another point on the line. If the slope is 0.5= 12, the rise is 1 and the run is 2. Therefore, we move 2 unit right and 1 unit up from the y-intercept to plot the second point.
We can now graph a line that passes through these two points. Note that the number of miles cannot be negative. Therefore, the minimum value of x is 0. This means that the line will be drawn only in the first quadrant of the coordinate plane.
We have the graph! Now we need to interpret the slope and the y-intercept. Remember that the y-intercept of an equation is its initial value. In this context, this can be interpreted as the initial fee.
We can also see that the total charge increases by $0.50 per mile.
This means that the slope of the line is the charge per mile. The best option that describes this situation is option C.
The graph below shows the total earnings of salespeople in a company based on the sales they make.
We want to decide which of the given statements could be true for the given graph. Let's write an equation in slope-intercept form to verify the statements. y= mx+ b In this form, m is the slope and b is the y-intercept. We can see that the line intercepts the y-axis at (0,1500).
The y-intercept of the line is 1500. Next, we will find the slope of the line. Let's choose two points on the line.
We can calculate the slope by substituting these values into the Slope Formula.
The slope of the line is 110. Now that we have th slope and the y-intercept, let's write the equation of the line. y= mx+ b ⇒ y= 1/10x+ 1500 Our next step is to organize the given statements in a table.
Statement | Sales ($) | Total Earnings ($) |
---|---|---|
A | 5000 | 2500 |
B | 0 | 0 |
C | 15 000 | 3000 |
D | 17 500 | 3300 |
Finally, we will substitute these values into the equation of the line to see which statement is true.
Statement | Sales ($) | Total Earnings ($) | Substitute | Verify |
---|---|---|---|---|
A | 5000 | 2500 | 2500? =1/10( 5000)+1500 | 2500 ≠ 2000 |
B | 0 | 0 | 0? =1/10( 0)+1500 | 0 ≠ 1500 |
C | 15 000 | 3000 | 3000? =1/10( 15 000)+1500 | 3000 = 3000 |
D | 17 500 | 3300 | 3300? =1/10( 17 500)+1500 | 3300 ≠ 3250 |
We found that statement C is correct.