Sign In
| | 17 Theory slides |
| | 11 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
In a nonproportional relationship, the line passes through the point (0,b), or the y-intercept. Use the Slope Formula to derive the equation for a nonproportional relationship. m=y_2-y_1/x_2-x_1
Assume that the other point the line passes through is (x,y).The applet shows the graphs of different equations. Analyze these lines.
The intercepts of a line provide information about the position of the line in the coordinate plane. They can be used to identify the equation of a line from known points or to graph a line from its equation.
The applet shows the graphs of different lines. Identify the intercepts of these lines.
A linear equation is an equation with at least one linear term and any number of constants. No other types of terms may be included. Linear equations in one variable have the following form, where a and b are real numbers and a≠ 0.
ax+b=0 or ax = b
Linear equations in two variables have the form below, where a, b, and c are real numbers and a≠ 0 and b≠ 0.
ax+by+c=0 or ax+by = c
A linear equation can be written in the following form called the slope-intercept form.
y=mx+b
In this form, m is the slope and b is the y-intercept. These are the general characteristics or parameters of the line. They determine the steepness and the position of the line on the coordinate plane. Consider the following graph.
This line has a slope of 2 and a y-intercept of 1. The equation of the line can be written in slope-intercept form using these values.
y= mx+ b ⇓ y= 2x+ 1The following applet generates linear equations. Those equations represent the relation between two variables x and y. Determine whether the generated equation is in slope-intercept form.
A linear equation in slope-intercept form has the following form. y=mx+b The slope m and y-intercept b are used to graph the equation. Consider the following function. y=2x-3 There are three steps to follow to graph it.
Jordan is investigating the fish population in Grassy Lake. The number of fish in the lake was counted as 60 in 2016.
She finds out that the population increases by 120 after each year. The following equation represents the fish population in the lake. y=120x+60 In this equation, y is the number of fish in the lake after x years.
y-intercept: Number of fish in the year 2016
y= mx+ b ⇓ y= 120x+ 60 The slope is 120 and the y-intercept is 60. This means that the line crosses the y-axis at (0, 60).
Next, move 1 unit to the right and 120 units up from the y-intercept to plot another point.
Finally, the graph of the equation can be competed by drawing a line passing through these two points.
Note that the number of years passed or the number of fish cannot be negative. Therefore, only the first quadrant of the coordinate plane is shown.
Slope &= 120 y-intercept &= 60 In this context, the slope 120 represents the increase in the fish population per year. The y-intercept 60 represents the number of fish in 2016.
The y-intercept b and the slope m of a line must be found to write the equation of the graph of the line in slope-intercept form . y=mx+b Consider the line shown as an example.
There are four steps to writing the equation of this line.
For this line, the rise is 6 and the run is 2. Substitute these values into the formula to calculate the slope of the line. m=6/2 ⇒ m=3
Jordan turns her attention to the cheetah population over years.
She finds a graph on the Internet that shows the number of cheetahs over years since 1900.
Jordan wants to represent the graph algebraically to interpret it further.
y-intercept: Number of cheetahs in the year 1900
y= mx+ b In this form, m is the slope and b is the y-intercept. The y-intercept of a line is the y-coordinate of the point where the line crosses the y-axis.
In the given graph, the line intercepts the y-axis at (0,100 000). This means that the y-intercept of the line is 100 000. Substitute 100 000 for b into the slope-intercept form of an equation. y= mx+ b ⇓ y= mx+ 100 000 The slope of a line is the ratio of the rise and run of the line. m=rise/run Any two points on the line can be chosen to determine the rise and run. One point can be the one where the line intercepts the y-axis. The other point can be (50,60 000) for simplicity.
The rise is -40 000 and the run is 50. Substitute these values into the ratio and calculate the slope.
rise= -40 000, run= 50
Put minus sign in front of fraction
Calculate quotient
The slope of the line is -800. Finally, the equation of the line can be completed by substituting -800 for m. y= mx+ 100 000 ⇓ y= -800x+ 100 000
y= -800x+ 100 000 The slope of the line is negative, which suggests that the number of cheetahs decreases by 800 per year. The y-intercept represents that there were 100 000 cheetahs in 1900.
y= 0
LHS+800x=RHS+800x
.LHS /800.=.RHS /800.
Calculate quotient
The equation suggests that cheetahs will go extinct after 125 years. The specific year can be found by adding 125 to the starting year 1900. 1900+125=2025 This means that if the current trend continues, cheetahs will go extinct in 2025.
The slope m and the y-intercept b of a line must be known to write a linear equation in slope-intercept form. y=mx+b When only two points on the line are known, the following four-step method can be used. For example, the equation of the line that passes through the points (- 4,1) and (8,4) will be written.
Substitute ( - 4, 1) & ( 8,4)
a-(- b)=a+b
Add and subtract terms
Calculate quotient
The slope m of the line passing through the two points is 0.25.
x= 8, y= 4
Multiply
LHS-2=RHS-2
Rearrange equation
Therefore, the y-intercept is 2.
Jordan is interested in endangered animals. She reads a magazine to learn what can be done to save these animals.
Suppose Jordan reads the same number of pages each day. The following table shows the number of pages y left in the magazine after x days.
| Number of Days x | 5 | 9 | 15 |
|---|---|---|---|
| Number of Pages y | 147 | 95 | 17 |
Which of the following equations represents the information in the table?
| Number of Days x | 5 | 9 | 15 |
|---|---|---|---|
| Number of Pages y | 147 | 95 | 17 |
| Point (x,y) | ( 5, 147) | ( 9, 95) | ( 15, 17) |
The slope of the relationship can be found by using the Slope Formula. m=y_2- y_1/x_2- x_1 Use any two of the points to calculate the slope!
Substitute ( 5, 147) & ( 9, 95)
Subtract terms
Put minus sign in front of fraction
Calculate quotient
The slope of the relationship is - 13. y= mx+ b ⇓ y= - 13x+ b Next, any of the points can be substituted into the above equation to find the y-intercept of the relation.
x= 15, y= 17
(- a)b = - ab
LHS+195=RHS+195
Rearrange equation
The y-intercept of the relationship is 212. Finally, the equation can be completed. y= -13x+ b ⇓ y= - 13x+ 212 This equation can also be rearranged as follows. y=- 13x+212 ⇔ y=212-13x
Write an equation in slope-intercept form using the given line, two points, or equation.
Determine the slope or y-intercept the given line based on its graph, points, or its equation. Be careful — the equation may or may not be written in slope-intercept form!
In a nonproportional relationship, the line passes through the point (0,b). The y-coordinate of this point is the y-intercept of the line. The Slope Formula will be used to derive the equation for a nonproportional relationship. m=y_2- y_1/x_2- x_1 Two points are needed to use the slope formula. If one of the points is ( 0, b), let the other point be ( x, y). This point could be any point that the line passes through. Then, substitute these points into the formula and solve for y.
Substitute ( 0, b) & ( x, y)
Subtract term
LHS * x=RHS* x
a/x* x = a
LHS+b=RHS+b
Rearrange equation
The following line represents the graph of a linear equation.
This line intersects both the x- and y-axis. Identify the intercepts of this line.
We will begin by identifying the points where the line intercepts the x- and y-axis.
Remember that the x-intercept of a line is the x-coordinate of the point where the line crosses the x-axis. The y-intercept of a line is the y-coordinate of the point where the line crosses the y-axis.
The x-intercept of the line is - 4 and the y-intercept is -1.
Which of the following linear equations are in slope-intercept form? Select all that apply.
Let's recall the slope-intercept form of a linear equation. y= mx+ b In this form, m is the slope and b is the y-intercept of the linear equation. We can identify that two of the given equations are in slope-intercept form. &y= 8x+ 10 &y= 3x+ 4
Jordan is studying the slope-intercept form of linear equations. Her homework is to identify the slope and the y-intercept of the following linear equation.
Help her find the slope and the y-intercept of this equation.
We want to identify the slope and the y-intercept of the given equation. Let's begin by writing it in slope-intercept form.
Remember that in slope-intercept form y= mx+ b, m is the slope and b is the y-intercept. y&=9x-43 & ⇕ y&= 9x+( - 43) The slope is 9 and the y-intercept is - 43.
A line passes through the point (0,2) with a slope of -2. Write the equation for this line in slope-intercept form.
We want to write an equation in slope-intercept form. Let's first remember slope-intercept form of a line. y= mx+ b In this form, m is the slope and b is the y-intercept of the line. We already know the slope of the line is - 2, so let's substitute this value into the equation. y= mx+ b ⇓ y= -2x+ b Next, we need to identify the y-intercept of the line. We are told that the line passes through (0,2). This point has the x-coordinate of 0, which means that this point is where the line intersects the y-axis. Therefore, the y-intercept of the line is 2. Let's substitute this value into the equation, too. y= -2x+ b ⇓ y= -2x+ 2 The equation of the line is y=-2x +2.
The graph represents the distance y in miles of a bus from Boston after x hours of a trip.
Write the equation for this graph in slope-intercept form.
We want to write an equation for the given graph in slope-intercept form. First, recall the formula for the slope-intercept form of a line. y= mx+ b In this form, m is the slope and b is the y-intercept of the line. Let's find the slope of the given line. We will choose two points on the line and use them to determine the rise and run of the line.
The rise is - 200 and the run is 4. Remember that the slope is the ratio of the rise to the run.
The slope of the line is -50. We can also see that the line intercepts the y-axis at (0,400). This means that the y-intercept is 400. Let's substitute these values into the slope-intercept form. y= mx+ b ⇓ y= - 50x+ 400 The equation of the line is y=-50+400.