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# Probability in Length, Area, and Volume

This lesson is will use various real-life situations to explore the concepts of geometric probability. It will be shown how geometric probability can be calculated for one-, two-, and three-dimensional objects.

### Catch-Up and Review

Here are a few recommended readings before getting started with this lesson.

## Calculating the Probability of Bumping Into a Person

Magdalena went to a sea resort with her family during her summer vacation. She noticed that when swimming in the pool with an area of 150 square meters, one person occupies approximately 2 square meters in the pool.

If there are already 30 people in the pool, what is the probability of Magdalena bumping into another person when she jumps into the pool?

## Geometric Probability

The geometric probability of an event is a ratio that involves geometric measures such as length, area, or volume. In geometric probability, points on a line segment, on a plane, or as part of a three-dimensional figure represent outcomes.

### Probability and Length

In one-dimensional figures, the probability that a point S, chosen at random from AD, lies on BC — the success region — is the ratio of the length of BC to the length of AD.

### Probability and Area

In two-dimensional figures, the probability that a point S, chosen at random from a region R, lies in region N — the success region — is the ratio of the area of region N to the area of region R.

### Probability and Volume

In three-dimensional figures, the probability that a point S, chosen at random from a solid C, lies inside a solid B — the success region — is the ratio of the volume of solid B to the volume of solid C.

## Probability of a Candy Falling on a Gray Square

Magdalena decorates a banana-honey cake she baked with candies. One of the candies fell on the floor and started to bounce. The floor consists of yellow and gray squares.

If there are 15 yellow squares of 2 square feet each and 18 gray squares of 3 square feet each, what is the probability of the candy falling on the gray region? Round the answer to two decimal places.

### Hint

Calculate the combined areas of the yellow and gray squares of the kitchen floor. Identify the area of the success region and the area of total region.

### Solution

It is given that there are 15 yellow squares of 2 square feet each and 18 gray squares of 3 square feet each. Therefore, by calculating the product of 15 and 2, as well as 18 and 3, the total areas of yellow and gray regions can be found.
The sum of these values is the total area of the kitchen floor. Note that the whole area of the kitchen floor is the sample space of all the possible outcomes where the candy can fall.
Since the probability of a candy falling on gray region should be calculated, the area of success region is the area of gray region. Therefore, the area of success region can be substituted with 54 and the number of total region can be substituted with 84 into the Probability Formula.
The probability of the candy falling on the gray area of the floor is approximately 0.64 or

## Calculating the Probability of Being Lost in a Forest

Magdalena is exploring a hidden and unknown country and gets lost. She knows that the makeup of the country consists of 8 great forests of approximately 1200 square kilometers each, 24 fields of 750 square kilometers each, and 76 lakes of 3 square kilometers each.

The total area of the country is 30000 square kilometers. Assuming that she is not in a lake, what is the probability of her being lost in a forest? In a field? Round the answer to two decimals.

### Hint

Start by calculating the total area of the forests, fields, and lakes. Then use the Probability Formula.

### Solution

First, the total areas of the forests, fields, and lakes should be calculated by multiplying the area of each geographical feature by the number of those features.

Object Number Area Total Area
Forests 8 1200
Fields 24 750
Lakes 76 3
It is given that the total area of the country is 30000 square kilometers. Since it is also given that Magdalena is not in a lake, the area of total region she could be in is the difference between the total area of the country and the total area of lakes.
Magdalena must be somewhere in a 29772 square kilometer area. To calculate the probability of the event of her being lost in a forest, substitute 9600, the total area of land covered by forests, for the area of success region and 29772 for the area of total region.
The probability of Magdalena being lost in a field can be calculated similarly by substituting 18000, the total land area made up of fields, for the area of success region and the same number for the area of total region.
Therefore, the probability of Magdalena being lost in a forest is approximately 0.32, or while the probability of her being lost in a field is about 0.60, or

## Calculating the Probability of Turning Successfully

Earlier geometric probabilities were calculated for two-dimensional problems. This time it will be shown how geometric probability can be used in a one-dimensional problem. Magdalena's friend Tiffaniqua was walking along a 170 foot long path in a park. Portions of the path are bordered by a fence.

In places where the path does not have a fence, Tiffaniqua can go and sit on the grass. She decides to close her eyes and randomly turn. If the probability of Tiffaniqua successfully turning and finding a place to lie on the grass to admire the sky is what is the total length of the fence?

### Hint

Use the formula for the geometric probability of length. Remember what the length of the success region represents.

### Solution

The geometric probability formula can be used to find the total length of the fence.
Since the probability of the event of turning and successfully finding a place in the grass is given, the length of success region is the length of parts without the fence. By substituting the length of total region with 170 and P with this value can be calculated.
51=Length of success region
Length of success region=51
It can be concluded that the length of the parts without the fence is 51 feet. The parts of the path without the fence form the sample space of the event of turning successfully. By subtracting 51 from the length of the path, the total length of the fence can be found.
Therefore, the length of the fence is 119 feet.

## Calculating the Probability of Different Positions of a Bubble

Next, the case in which the geometric probability of a three-dimensional object can be calculated will be presented. Two scientists are conducting an experiment in which they place a small bubble of water into a vacuum sphere.

Assuming that the bubble is equally likely to be anywhere within the sphere, what is the probability that it lands closer to the outside of the sphere than its center? Give an exact answer as a fraction in its simplest form.

### Hint

Think of how the outcomes in which the bubble is closer to the outside than the center of the sphere can be described. Try to relate them to the radius of the sphere.

### Solution

The experiment uses a sphere, a three-dimensional object, so the geometric probability formula for volume should be used.
The sample space in this case is the whole region inside the sphere. The volume of total region is the same as the volume of the sphere. Let r be the radius of the sphere. Its volume is then determined by the following formula.
Outcomes in which the bubble is situated closer to the outside than the center of the sphere are said to be the success outcomes.
They can be calculated as the difference between the total volume of the sphere and the outcomes in which the bubble is situated closer to the center of the sphere.
The bubble is closer to the center if it is in the sphere whose radius is half the radius of the whole sphere. The radius of this smaller sphere is This means that the volume of that sphere is as follows.
Simplify right-hand side
Now the volume of the success outcomes can be found.
Simplify right-hand side
Finally, the found volumes can be substituted into the probability formula.
Substitute values and evaluate
It can be concluded that the probability of the bubble being closer to the outside of the sphere is

## Calculating the Probability of the Girls Meeting at the Library

Magdalena and Tiffaniqua decided to meet at the school library before going home after school. Since the girls take different classes, they could arrive at two random times between 14:30 and 16:00 Magdalena and Tiffaniqua agreed to wait exactly 15 minutes for each other to arrive before leaving.

What is the probability that Magdalena and Tiffaniqua will see each other? Give the answer as a fraction in the simplest form.

### Hint

Draw a graph in which the x- and y-axes represent Tiffaniqua's and Magdalena's timelines. Think of how the success region can be identified.

### Solution

First, draw a graph that represents the possible times in which Magdalena and Tiffaniqua could meet. If Tiffaniqua arrives at 14:30 then Magdalena must arrive no later than 14:45 If Tiffaniqua arrives at 14:31 Magdalena must arrive no later than 14:46 and so on.

Therefore, the 15-minute leeway shown on the graph represents their opportunity of meeting. The geometric probability formula for area will be used to calculate the probability of both girls being in that 15-minute span.

### Area of the Total Region

The total time available for the girls to meet or a sample space is represented by the square shown in the diagram. Its sides represent the 90-minute time span from 14:30 to 16:00

The area of the total region can be calculated by substituting 90 for s into the area of a square formula.

### Area of the Success Region

Analyzing the diagram, it can be noted that the area of the 15-minute time allowance is equal to the difference between the area of the square and the areas of the top and bottom triangles. Also, the areas of the top and bottom triangles are the same, so calculating only one of them would be enough.

As can be seen, these are right triangles whose legs represent 75 minutes. By using the area of a triangle formula, their areas can be calculated.
Substitute values and evaluate
Now, the area of the 15-minute leeway zone can be found.
Therefore, the area of success region is 2475.

### Calculating Probability

Finally, by substituting 2475 for the area of the success region and 8100 for the area of the total region, the probability of the event of the girls meeting can be calculated.
It can be concluded that the probability that Magdalena and Tiffaniqua will meet at the library is

## Calculating Probability of Hitting Different Regions on a Dartboard

On a standard dartboard, the diameter of the center red circle is 2 centimeters and the diameter of the green circle around it is 2 centimeters greater. Each rectangle has the width of 1.5 centimeters. Some other lengths are given on the diagram.

A dart is thrown at the dartboard.

a What is the probability of the dart hitting a red region? Round the answer to 3 decimals.
b What is the probability of the dart hitting a red or green region? Round the answer to 3 decimals.
c What is the probability of the dart hitting a black or white region? Round the answer to 3 decimals.

### Hint

a Calculate the radii of all of the circles on the dartboard and then use them to find the areas of the circles. What is the total area of all the red regions? Calculate the areas in terms of pi.
b Use the geometric probability formula.
c Note that if a dart did not hit neither red nor green region, then it must have hit white or black region. Use the Complement Rule.

### Solution

a In order to find the probability of hitting a red region with a dart, the geometric probability formula can be used.
To use the formula, first the areas of the success region — the red region — and total regions should be found. For the purposes of the solution the circles on the board can be named.
First, the radii of all the circles can be found. It is given that the diameter of the small red circle C1 at the center of the dartboard is 2 centimeters, so its radius is centimeter.
The diameter of the green circle C2 is said to be 2 centimeters greater than the diameter of C1. This implies that the diameter of C2 is 2+2=4 centimeters and its radius is 2 centimeters. It is given that the length between C2 and the next ring is 8 centimeters, so the radius of C3 is obtained by adding 2 and 8.
Next, by adding the width of the rectangles to the radius of C3, it can be concluded that the radius of C4 is 11.5 centimeters.
The radius of C5 is equal to the sum of 14 and radius of C2, which is 2 centimeters. Finally, the radius of C6 is 1.5 centimeters greater than
Now that all the radii are known, they can be substituted into the circle area formula. First, the area of C1 can be found. Leave the areas in terms of pi to get a precise result at the end.
Similarly, the areas of the rest of the circles can be calculated.
C1 1 π(1)2 π
C2 2 π(2)2 4π
C3 10 π(10)2 100π
C4 11.5 π(11.5)2 132.25π
C5 16 π(16)2 256π
C6 17.5 π(17.5)2 306.25π
By calculating the difference between the areas of C4 and C3, the total area of smaller red and green rectangles can be found.
Since there are 20 rectangles and they all have the same size, the area of each rectangle can be calculated by dividing 23.25π cm2 by 20.
10 of the 20 rectangles are red, so the total area of the red rectangles is 16.125π square centimeters. Finally, the total area of the greater green and red rectangles can be found as the difference between the areas of C6 and C5.
The area of each bigger rectangle can be obtained by dividing this value by 20.
Just as in case with smaller rectangles, there are 10 bigger red rectangles, so the total area of the bigger red rectangles is 25.125 square centimeters. The total red region on the board consists of 1 10 and 10 Therefore, the total area of the red region is the sum of these areas.
The area of the success region was found to be 42.25 square centimeters. The area of the total region is the area of the largest circle C6. With this information in mind, the probability of the dart hitting a red region can be found.
The probability of the dart hitting a red region is about 0.138, or
b Since the dart can hit the red or the green regions, the success region is the total area of both colors. Earlier it was found that the total areas of the small and big rectangles are 32.25π and 50.25π square centimeters, respectively. Also, square centimeters is the area of the center circles.
The total area of the success region is 86.5π square centimeters. The area of total region is the same as before, 306.25π square centimeters. Now enough information has been calculated to find the probability of hitting a red or green region.
The probability of hitting a red or green region is approximately 0.282, or
c Note that if a dart did not hit neither red nor green region, then it must have hit white or black region. In other words, hitting a white or black region is a complement of the event of hitting red or green region. Therefore, using the Complement Rule, the probability of hitting white or black region can be found.
P(black or white)=1P(red or green)
P(black or white)=10.282
P(black or white)=0.718
The probability of hitting a black or white region is approximately 0.718, or

## Finding Probability Using the Values of Area

Magdalena went to a sea resort with her family during her summer vacation. She noticed that when swimming in the pool with an area of 150 square meters, one person occupies approximately 2 square meters in the pool.

If there are already 30 people in the pool, what is the probability of the event of Magdalena bumping into another person when she jumps into the pool? Give the answer as a fraction in the simplest form.

### Hint

Use the Probability Formula. What is the area of the success region?

### Solution

It is given that there are 30 people in the pool, each occupying 2 square meters. By multiplying these values, the area occupied by all the people in the pool can be calculated.
The area of the pool occupied by other swimmers is 60 square meters. The Probability Formula can be used to calculate the probability of Magdalena bumping into another person. The area of the success region and the area of the total region should be substituted with 60 and 150, respectively.
It can be concluded that the probability of Magdalena bumping into a person in the pool is