Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 11 Page 577

Start by drawing a segment from A to any of the vertices. Use this segment to construct a 90^(∘) angle.

Practice makes perfect

We are given a quadrilateral with vertices P, Q, R, and S, and a point of rotation A.

We want to rotate PQRS by 90^(∘) about point A. To do so, we will follow four steps.

  1. Draw AR and construct a 90^(∘) angle with vertex A and side AR.
  2. Construct AR' such that AR' lies on a side of the angle drawn in the previous step and AR'≅ AR.
  3. Locate P', Q' and S' in a similar manner.
  4. Connect P', Q', R' and S' to draw the quadrilateral P'Q'R'S'.

Let's do it!

Step 1

Let's draw AR.

We will use a protractor to construct a 90^(∘) angle with vertex A and side AR. We start by placing the center of the protractor on A, making sure that the flat part is on AR.

Notice that the inner measuring scale has 0^(∘) on AR. Therefore, we will use the inner measuring scale. Moreover, recall that if it is not specified we measure the angle in the counterclockwise direction.

Finally, to construct the angle, we remove the protractor and draw a ray from A that passes through the mark we have just drawn.

Note that for this step we could have chosen point P, point Q or point S instead of R. We arbitrarily chose point R for simplicity.

Step 2

We will now locate R', which is the image of R after the rotation. To do so we will use a compass. We will start by placing the sharp spike of the compass at A, and the leg with the pencil at R.

Without modifying the amplitude of the compass, we will keep the sharp spike at A. Then we will draw an arc intersecting the ray we drew in the previous step. This point of intersection is R'.

Step 3

We can repeat Step 1 and 2 to find Q'.

We can apply the same steps to locate P'.

Then, we can repeat the same steps to locate S'.

Step 4

Finally, to draw the quadrilateral PQRS — which is the image of the quadrilateral PQRS after a rotation of 90^(∘) about A — we will connect the obtained vertices.