Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
6. Dilations
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Exercise 61 Page 593

Corresponding sides of similar polygons are proportional.

4

Practice makes perfect

We want to find the value of a, which is the length of TU. We are given that TRSU ~ NMYZ.

Since the polygons are similar, we know that the lengths of corresponding sides are proportional. T U/N Z=T R/N M Knowing this proportion, we can solve for any missing side length using any three known side lengths. In this case, we know the lengths of sides TR, NM, and NZ. Therefore, we can find TU by substituting these lengths in the above proportion.
TU/NZ=TR/NM
TU/6=3/4.5
â–Ľ
Solve for TU
TU=3/4.5* 6
TU=18/4.5
TU=4
Therefore, the value of a is 4.