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Start by identifying the hypotenuse of the right triangle. Then find the sides that are opposite and adjacent to ∠ M.
sin M=sqrt(3)/2, cos M=1/2, tan M=sqrt(3)
We see that the length of the hypotenuse is 4. The length of the side adjacent to ∠ M is 2 and the length of the side opposite to ∠ M is 2sqrt(3). With this information, we can find the desired ratios.
Ratio | Definition | Value |
---|---|---|
sin M | Length of leg opposite∠ M/Length of hypotenuse | 2sqrt(3)/4=sqrt(3)/2 |
cos M | Length of leg adjacent∠ M/Length of hypotenuse | 2/4=1/2 |
tan M | Length of leg opposite∠ M/Length of leg adjacent∠ M | 2sqrt(3)/2=sqrt(3) |
Later in the book we will learn that the sine, cosine, and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant, secant, and cotangent. These terms are often shortened to csc, sec, and cot, respectively. csc θ = hypotenuse/opposite, sec θ = hypotenuse/adjacent cot θ = adjacent/opposite In the given right triangle, the length of the hypotenuse is 4. The length of the side adjacent to ∠ M is 2 and the length of the side opposite to ∠ M is 2 sqrt(3). With this information, we can also find the reciprocal ratios of the ratios that we found in the exercise.
Ratio | Definition | Value |
---|---|---|
csc M | Length of hypotenuse/Length of leg opposite∠ M | 4/2sqrt(3)=2sqrt(3)/3 |
sec M | Length of hypotenuse/Length of leg adjacent∠ M | 4/2=2 |
cot M | Length of leg adjacent∠ M/Length of leg opposite∠ M | 2/2sqrt(3)=sqrt(3)/3 |