Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Trigonometry
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Exercise 13 Page 510

Start by identifying the hypotenuse of the right triangle. Then find the sides that are opposite and adjacent to ∠ M.

sin M=sqrt(3)/2, cos M=1/2, tan M=sqrt(3)

Practice makes perfect
For the given right triangle, we want to write the ratios for the sine, cosine, and tangent of ∠ M. Let's start by identifying the hypotenuse of the triangle and the sides that are opposite and adjacent to ∠ M.

We see that the length of the hypotenuse is 4. The length of the side adjacent to ∠ M is 2 and the length of the side opposite to ∠ M is 2sqrt(3). With this information, we can find the desired ratios.

Ratio Definition Value
sin M Length of leg opposite∠ M/Length of hypotenuse 2sqrt(3)/4=sqrt(3)/2
cos M Length of leg adjacent∠ M/Length of hypotenuse 2/4=1/2
tan M Length of leg opposite∠ M/Length of leg adjacent∠ M 2sqrt(3)/2=sqrt(3)

Extra

Reciprocal Ratios

Later in the book we will learn that the sine, cosine, and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant, secant, and cotangent. These terms are often shortened to csc, sec, and cot, respectively. csc θ = hypotenuse/opposite, sec θ = hypotenuse/adjacent cot θ = adjacent/opposite In the given right triangle, the length of the hypotenuse is 4. The length of the side adjacent to ∠ M is 2 and the length of the side opposite to ∠ M is 2 sqrt(3). With this information, we can also find the reciprocal ratios of the ratios that we found in the exercise.

Ratio Definition Value
csc M Length of hypotenuse/Length of leg opposite∠ M 4/2sqrt(3)=2sqrt(3)/3
sec M Length of hypotenuse/Length of leg adjacent∠ M 4/2=2
cot M Length of leg adjacent∠ M/Length of leg opposite∠ M 2/2sqrt(3)=sqrt(3)/3