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Divide the given quadrilateral into a rectangle and a right triangle.
a=14, b=6sqrt(2)
Let's divide the given quadrilateral into a rectangle and a right triangle.
We will deal with these two shapes one at a time.
Therefore, we have a 45^(∘)-45^(∘)-90^(∘)- triangle. In this type of triangle, the legs are congruent and the length of the hypotenuse is sqrt(2) times the length of a leg. With this information, we can find the length of the hypotenuse and missing leg. b&= sqrt(2) * 6=6sqrt(2) c&= 6 Let's add these newly found side lengths to the triangle.
Let's consider the given shape and the previously obtained information. Let s be the length of the bottom side of the rectangle.
Since opposite sides of a rectangle are congruent, we can conclude that s=8. We can find the value of a using the Segment Addition Postulate. a=8+6 ⇔ a=14