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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

Cumulative Standards Review

Exercise 8 Page 427

Use the Converse of Same-Side Interior Angles Postulate.

I

Practice makes perfect

We need to find out what value of x makes the lines g and h parallel.

For that, let's recall the Converse of Same-Side Interior Angles Postulate. This theorem tells us that if two lines and a transversal form same-side interior angles that are supplementary, then the two lines are parallel. (2x+10)^(∘)+(5x-5)^(∘) = 180^(∘) ⇒ g ∥ h We will now find the value of x that satisfies the equation.

(2x+10)+(5x-5)=180

Remove parentheses

2x+10+5x-5=180

Add terms

7x+5=180

LHS-5=RHS-5

7x=175

.LHS /7.=.RHS /7.

x=25

We have that x=25 is the solution. Therefore, for x=25 lines g and h are parallel. This corresponds to answer I.

Subchapter links

Exercises p.426-428