Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
4. Medians and Altitudes
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Exercise 22 Page 313

The centroid of a triangle is the intersection of at least two medians in the triangle. The orthocenter is the intersection of at least two altitudes in the triangle.

Centroid:

Orthocenter:

Practice makes perfect

Let's draw an arbitrary acute scalene triangle, â–ł LMN.

Centroid

To find the centroid we have to draw at least two medians of the triangle, which is the segment between a vertex and the midpoint of the vertex's opposite side. Since the perpendicular bisector of a segment goes through its midpoint, we should find the perpendicular bisectors of two sides.

Finding Perpendicular Bisectors

Let's find the perpendicular bisector for NL. Open up a compass so that its width is greater than half the distance of NL, and draw two intersecting arcs using N and L as centers.

The line that contains both points of intersection is the perpendicular bisector to NL.

Let's repeat the process for MN.

Finding the Centroid

By drawing segments from M and L to the midpoint of their opposite sides, we can locate the centroid at the intersection of these segment.

Orthocenter

To find the orthocenter, we have to draw at least two altitudes of the triangle which is the perpendicular segment from a vertex of the triangle to the line containing the opposite side.

Finding Perpendicular Lines

To find the line through M that is perpendicular to NL, open up a compass so that its width is greater than the width between M and NL, and draw an arc that intersects this side at two points.

Next, using the arcs intersection with NL, draw a pair of intersecting arcs below M.

The ray that contains both M and the arc's intersection is perpendicular to NL.

Let's repeat the process for ML.

Finding the Orthocenter

The orthocenter is the point of intersection of the altitudes drawn from M and N.