body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

Chapter Test

Continue to next subchapter

Exercise 9 Page 345

Start by finding the third angle of the triangle using the Triangle Angle-Sum Theorem.

ST, RS, RT

Practice makes perfect

We want to order the sides of the given triangle from shortest to longest.

First, let's find the third angle of the triangle using the Triangle Angle-Sum Theorem.

m∠ R + m∠ S+m∠ T=180

m∠ R= 30, m∠ S= 80

30 + 80+ m∠ T=180

▼

Solve for m∠ T

Add terms

110+m∠ T = 180

LHS-110=RHS-110

m∠ T=70

Let's add this newly found measurement to the triangle.

We know that, if two angles of a triangle are not congruent, then the longer side lies opposite the larger angle. Applying this fact, we can order the sides from shortest to longest. ccccc 30^(∘) & < & 70^(∘) & < & 80^(∘) m∠ R & < & m∠ T & < & m∠ S ST & < & RS & < & RT