Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Cumulative Standards Review

Exercise 23 Page 136

What can you say about the angles by looking at the graph?

See solution.

Practice makes perfect
We are given that ∠ 1 and ∠ 2 are supplementary. From the graph we can tell that their sides are opposite rays, so they are also vertical angles. Let's summarize the given information and the desired outcome of the proof. Then, we can write a paragraph proof! Given:& ∠ 1 and ∠ 2 are supplementary. & ∠ 1 and ∠ 2 are vertical. Prove:& ∠ 1 and ∠ 2 are right angles We know that the angles are vertical, so we can use the Vertical Angles Theorem. It says that vertical angles are congruent. Thus, we can conclude that ∠ 1 ≅ ∠ 2. Since they are congruent, they have the same measures, m ∠ 1 = m ∠ 2. \begin{gathered} \underline\textbf{Statement}\\ \angle 1 \text{ and } \angle 2 \text{ are vertical because it is given.}\\ \text{ By the Vertical Angles Theorem, }\\ \text{they are congruent.}\\ \text{Since } \angle 1 \cong \angle 2, \text{ then } m \angle 1= m \angle 2. \end{gathered}

These angles are also supplementary. Recall that supplementary angles are two angles whose measures have a sum of 180. Therefore, we can conclude that the measures of ∠ 1 and ∠ 2 add to 180. \begin{gathered} \underline\textbf{Statement}\\ \angle 1 \text{ and } \angle 2 \text{ are supplementary}\\ \text{because it is given.} \\ \text{ By the definition of supplementary angles,}\\ m \angle 1 + m \angle 2 =180. \end{gathered} Since m ∠ 1= m ∠ 2, then we can use the Substitution Property of Equality and substitute m ∠ 2 for m ∠ 1 in m ∠ 1 + m ∠ 2 =180. \begin{gathered} \underline\textbf{Statement}\\ m \angle 1= m \angle 2 \text{ and } m \angle 1 + m \angle 2 =180. \\ \text{Substitute } {\color{#009600}{m \angle 2}} \text{ for } m \angle 1. \\\text{ By the Substitution Property of Equality, }\\ {\color{#009600}{m \angle 2}} + m \angle 2 =180. \end{gathered} Notice that if we simplify the left-hand side we will get 2 m ∠ 2=180. Then, we can use the Division Property of Equality and divide both sides by 2, which will give us m ∠ 2 =90. \begin{gathered} \underline\textbf{Statement}\\ \text{Simplify the left-hand side.} \\ \text{By the Division Property of Equality, } \\ m \angle 2 =90. \end{gathered} Recall that ∠ 1 and ∠ 2 are congruent, thus m ∠ 1 is also 90. Since an angle with a measure of 90 is a right angle, then we can conclude that both ∠ 1 and ∠ 2 are right angles. This is what we wanted to prove! \begin{gathered} \underline\textbf{Statement}\\ \angle 1 \cong \angle 2, \text{ so } m \angle 1 =90. \\ \text{Angles with a measure of }90 \text{ are right angles,} \\ \text{so }m \angle 1 \text{ and } m \angle 2 \text{ are right angles.} \end{gathered}

Final Proof

Given:& ∠ 1 and ∠ 2 are supplementary. & ∠ 1 and ∠ 2 are vertical. Prove:& ∠ 1 and ∠ 2 are right angles Proof: ∠ 1 and ∠ 2 are vertical because it is given. By the Vertical Angles Theorem, they are congruent. Since ∠ 1 ≅ ∠ 2, then m ∠ 1=m∠ 2. ∠ 1 and ∠ 2 are supplementary because it is given. By the definition of supplementary angles, we know the following. m ∠ 1+ m∠ 2 =180 m ∠ 1 =m ∠ 2 and m ∠ 1+ m ∠ 2 =180. Substitute m ∠ 2 for m ∠ 1. By the Substitution Property of Equality, we know the following. m ∠ 2+ m∠ 2 =180 Simplify the left-hand side. By the Division Property of Equality, m ∠ 2=90. ∠ 1 ≅ ∠ 2, so m ∠ 1=90. Angles with a measure of 90 are right angles, so m ∠ 1 and m ∠ 2 are right angles.