Pearson Geometry Common Core, 2011
PG
Pearson Geometry Common Core, 2011 View details
Cumulative Standards Review

Exercise 10 Page 819

G

Practice makes perfect

First, let's take a look at the given circle.

Now, recall the standard form of an equation of a circle.

(x- h)^2+(y- k)^2= r^2 In this form, ( h, k) is the center of the circle and r is its radius. Let's consider our circle once again and identify its center and radius.

As we can notice on the diagram, the center of the circle is ( - 3, 2) and its radius is 4. This information is enough to write the equation. (x-( - 3))^2+(y- 2)^2= 4^2 ⇕ (x+3)^2+(y-2)^2=16 The obtained equation corresponds to option G.