We know that M is the of XY.
Since
M is the midpoint, we know that the lengths of
XM and
MY are equal. Thus, we can write the following equation.
x2−2=x
Now, we will solve this equation for
x. We will start by subtracting
x from both sides. Then we can .
x2−2=x⇔x2−x−2=0
To factor this equation, we need to think of two numbers that add to be
-1 and multiply to be
-2. We can imagine that this will be some combination of
±1 and
±2.
Factor m
|
Factor n
|
m+n
|
mn
|
2
|
1
|
3
|
2
|
2
|
-1
|
1
|
-2
|
-2
|
1
|
-1
|
-2
|
-2
|
-1
|
-3
|
2
|
The that allow for this are
-2 and
1. Now we can write the of the equation.
Equation: Factored: x2−x−2=0(x−2)(x+1)=0
In order to have the entire equation equal
0, one of the factors must be equal to
0 by the .
Factored: Factors: Solutions: (x−2)(x+1)=0 x−2=0orx+1=0x=2orx=-1
Since the measure of any length
cannot be negative,
x must be
2.
We can check that we factored our quadratic equation correctly by multiplying the binomials and making sure that the product matches the given equation. Remember to multiply both terms in the first binomial by both terms in the second binomial ().
(x−2)(x+1)=0
(x⋅x)+(-2⋅x)+(x⋅1)+(-2⋅1)=0
(x2)+(-2x)+(x)+(-2)=0
x2−2x+x−2=0
x2−x−2=0
Finally, we can add
x to both sides to fully return to the original equation.
x2−x−2=0⇒x2−2=x