Exercise 37 Page 162

We will determine the $x\text{-}$ and $y\text{-}$intercepts one at a time. Let's start with the $x\text{-}$intercept.

Finding the $x\text{-}$intercept

Think of the point where the graph of an equation crosses the $x\text{-}$axis. The $y$-value of that $(x,y)$ coordinate pair is $0,$ and the $x$-value is the $x\text{-}$intercept. To find the $x\text{-}$intercept of the equation, we should substitute $0$ for $y$ and solve for $x.$