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Graph the given system and determine the vertices of the overlapping region. Substituting these vertices into the equation will help you find the minimum value.
Graph:
Vertices: (25,110), (75,110), (25,260/3), (75,20)
Minimum: 633.3 at (25,260/3)
Our first step in finding the minimum value of the given equation is to graph the system and determine the vertices of the overlapping region. Substituting these vertices into the equation, we will find the minimum value. 25≤ x ≤ 75 & (I) y ≤ 100 & (II) 8x+6y ≥ 720 & (III)
To graph a compound inequality, we can separate it into two cases. Compound Inequality:& 25 ≤ x ≤ 75 Case I:& 25 ≤ x Case II:& x ≤ 75 To make things a bit more simple, we will draw the graph of each case and then combine them.
The inequality 25 ≤ x describes all values of x that are greater than or equal to 25. This means that every coordinate pair with an x-value that is greater than or equal to 25 will be included in the shaded region. Notice that the inequality is not strict, so the boundary line will be solid.
Since the inequality represents the values of x that are less than or equal to 75, every coordinate pair with an x-value that is less than or equal to 75 will be included in the shaded region. The boundary line will be solid because the inequality is non-strict.
Let's draw the graphs of both cases on the same coordinate plane and shade the overlapping region. This will give us the graph of the compound inequality.
The inequality y≤ 110 tells us that all coordinate pairs with a y-coordinate that is less than or equal to 110 will be in the solution set of the inequality. Because the inequality is non-strict, the boundary line will be solid.
To write the equation of the boundary line for the third inequality, we will first isolate the y-variable.
We can write the equation of the boundary line by changing the inequality symbol to an equals sign. Inequality:& y≥-4/3x+120 Boundary Line:& y=-4/3x+120 Since this equation is in slope-intercept form, we can determine its slope m and y-intercept b to draw the line. Slope-Intercept Form:& y= mx+b Boundary Line:& y= -4/3x+120 Now that we know the slope and y-intercept, let's use these to draw the boundary line. Notice that the inequality is non-strict, which means that the line will be solid.
To complete the graph, we will test a point that is not on the line and decide which region we should shade. Let's test the point ( 0, 0). If the point satisfies the inequality, we will shade the region that contains the point. Otherwise, we will shade the other region.
Since the point does not satisfy the inequality, we will shade the region that does not contain the point.
Let's draw the graphs of the inequalities on the same coordinate plane.
Now that we can see the overlapping region, let's highlight the vertices.
Looking at the graph, we can see that the line y=110 intersects the lines x=25 and x=75 at the points (25,110) and (75,110), respectively. These are two of the vertices. ( 25, 110) and ( 75, 110) We know the x-coordinates of the other vertices are 25 and 75. We will find their y-coordinates by substituting them into the equation y=- 43x+120. Let's do it!
The third vertex is ( 25, 2603). Next, we will determine the final vertex.
x= 75
Multiply
Calculate quotient
Add terms
The last vertex is ( 75, 20).
Substituting the vertices into the given equation, C=8x+5y, we will determine its minimum value. Let's start with the vertex ( 25, 110).
For the vertex ( 25, 110), the value of the equation is 750. We can determine the values of the equation for the other vertices in the same way.
| Vertex | C=8x+5y | Value |
|---|---|---|
| ( 25, 110) | C=8( 25)+5( 110) | C=750 |
| ( 75, 110) | C=8( 75)+5( 110) | C=1150 |
| ( 25, 260/3) | C=8( 25)+5( 260/3) | C=633.3 |
| ( 75, 20) | C=8( 75)+5( 20) | C=700 |
Looking at the table, we can see that the minimum value of the equation is C=633.3.