body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 2 Common Core, 2011

PA

Pearson Algebra 2 Common Core, 2011 View details

4. Linear Programming

Continue to next subchapter

Exercise 10 Page 160

Graph the given system and determine the vertices of the overlapping region. Substituting these vertices into the equation will help you find the maximum value.

Graph:

Vertices: $(0, 0),$ $(0, 8),$ $(2, 6),$ $(5, 0)$
Maximum: $500$ at $(5, 0)$

Practice makes perfect

Our first step in finding the maximum value of the given equation is to graph the given system and determine the vertices of the overlapping region. Substituting these vertices into the equation, we will find the maximum value.

⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎧ x + y \leq 8 2 x + y \leq 10 x \geq 0 y \geq 0 (I) (II) (III) (IV)

Inequality I

To write the equation of the boundary line for the first inequality, we will change the inequality symbol to an equals sign.

Inequality : Boundary Line : x + y \leq 8 x + y = 8

Let's rewrite this equation in slope-intercept form.

x + y = 8

$LHS - x = RHS - x$

y = - x + 8

Now we can determine its slope

m

and

y -

b

to draw the line.

Slope - Intercept Form : Boundary Line : y = m x + b y = - 1 x + 8

Now that we know the slope and

y -

intercept, let's use these to draw the boundary line. Notice that the inequality is non-strict, which means that the line will be solid.

Subchapter links

Lesson Check p.160

Practice and Problem-Solving Exercises p.160-162

Standardized Test Prep p.162

Mixed Review p.162