Pearson Algebra 2 Common Core, 2011
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Pearson Algebra 2 Common Core, 2011 View details
2. Matrix Multiplication
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Exercise 48 Page 779

Calculate (P+Q)(R+S). Then, calculate PR+PS+QR+QS and compare the results.

The expressions are equal.

Practice makes perfect

We want to determine whether the two expressions are equal. (P+Q)(R+S)andPR + PS + QR + QS Before we start calculating, let's note that the dimensions of every given matrix are the same, 2* 2. Therefore, addition and multiplication of every pair of the given matrices are possible. Also, each product will have dimensions 2* 2, which means that every operation in this exercise will be well defined. Let's evaluate each expression one at a time.

(P+Q)(R+S)

Let's start with the first expression. (P+Q)(R+S) First, we will calculate P+Q. P Q [ cc 3&4 1&2 ] + [ cc 1&0 3& -2 ] 2* 2 2* 2 Let's do it!
3&4 1&2 + 1&0 3& -2

Add matrices

3+1&4+0 1+3&2+(-2)
4&4 4&0
Now let's calculate R+S. R S [ cc 1&4 -2 &1 ] + [ cc 0&1 2&0 ] 2* 2 2* 2 Here we go!
1&4 -2 &1 + 0&1 2&0

Add matrices

1+0&4+1 -2+2&1+0
1&5 0&1
Finally, we can calculate (P+Q)(R+S). To multiply matrices, we use a process called the dot product. It follows a pattern of multiplying and adding terms across the rows of the first matrix and down the columns of the second one. [ cc a& b c&d ] * [ cc e&f g&h ] = [ cc a e+ b g&af+bh ce+dg&cf+dh ] Let's apply this.
4&4 4&0 * 1&5 0&1
4(1)+4(0)&4(5)+4(1) 4(1)+0(0)&4(5)+0(1)
4+0&20+4 4+0&20+0
4&24 4&20

PR+PS+QR+QS

Next, let's consider the other expression. PR+PS+QR+QS Let's calculate PR first. P R [ cc 3&4 1&2 ] * [ cc 1&4 -2 &1 ] 2* 2 2* 2 Let's do it!
3&4 1&2 * 1&4 -2 &1
3(1)+4(-2)&3(4)+4(1) 1(1)+2(-2)&1(4)+2(1)
3-8&12+4 1-4&4+2
-5&16 -3&6
Next, we will calculate PS. P S [ cc 3&4 1&2 ] * [ cc 0&1 2&0 ] 2* 2 2* 2 Let's do it!
3&4 1&2 * 0&1 2&0
3(0)+4(2)&3(1)+4(0) 1(0)+2(2)&1(1)+2(0)
0+8&3+0 0+4&1+0
8&3 4&1
Now, we will calculate QR. Q R [ cc 1&0 3& -2 ] * [ cc 1&4 -2 &1 ] 2* 2 2* 2 Let's do it!
1&0 3& -2 * 1&4 -2 &1
1(1)+0(-2)&1(4)+0(1) 3(1)+(-2)(-2)&3(4)+(-2)(1)
1+0&4+0 3+4&12-2
1&4 7&10
We also need to calculate QS. Q S [ cc 1&0 3& -2 ] * [ cc 0&1 2&0 ] 2* 2 2* 2 Let's do it!
1&0 3& -2 * 0&1 2&0
1(0)+0(2)&1(1)+0(0) 3(0)+(-2)(2)&3(1)+(-2)(0)
0+0&1+0 0-4&3+0
0&1 -4&3
Finally, we are ready to calculate the sum PR+PS+QR+QS.
-5&16 -3&6 + 8&3 4&1 + 1&4 7&10 + 0&1 -4&3

Add matrices

-5+8+1+0&16+3+4+1 -3 +4+7+(-4) &6+1+10+3
4&24 4&20

Comparing the Expressions

The expressions turned out to be equal. (P+Q)(R+S) = 4&24 4&20 = PR+PS+QR+QS This result should not be a surprise to us. We know that matrix multiplication of square matrices has the Distributive Property. If we use this property a few times on the expression (P+Q)(R+S), we will obtain the other expression.
(P+Q)(R+S)
(P+Q)R+(P+Q)S
â–Ľ
Distribute R & S
PR+QR+(P+Q)S
PR+QR+PS+QS
Therefore, as long as the matrices P, Q, R, and S are square matrices of the same dimensions, the two given expressions will be always equal.