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Start by identifying the values of a, b, and c.
(6x+7)(9x+4)
Here we have a quadratic trinomial of the form ax^2+bx+c, where |a| ≠ 1 and there are no common factors. To factor this expression, we will rewrite the middle term, bx, as two terms. The coefficients of these two terms will be factors of ac whose sum must be b.
54x^2+87x+28
We have that a= 54, b=87, and c=28. There are now three steps we need to follow in order to rewrite the above expression.
c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result 12 &126 &12 + 126 &138 14 &108 &14 + 108 &122 18 &84 &18 + 84 &102 21 &72 &21 + 72 &93 24 & 63 & 24 + 63 &87
Finally, we will factor the last expression obtained.
Factor out 6x
Factor out 7
Factor out (9x+4)
Distribute (6x+7)
Distribute 9x
Distribute 4
Add terms
We can see above that after expanding and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!