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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

Chapter Test

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Exercise 23 Page 539

Is there a greatest common factor between all of the terms in the given expression? If so, you should factor that out first.

3n^2(n+3)(2n-1)

Practice makes perfect

We want to completely factor the given expression. To do so, we will first identify and factor out the greatest common factor.

Factor Out the GCF

The greatest common factor (GCF) of an expression is a common factor of the terms in the expression. It is the common factor with the greatest coefficient and the greatest exponent. The GCF of the given expression is 3n^2.

6n^4+15n^3-9n^2

SplitIntoFactors

Split into factors

3n^2(2n^2)+ 3n^2(5n)- 3n^2(3)

Factor out 3n^2

3n^2(2n^2+5n-3)

Factor the Quadratic Trinomial

Here we have a quadratic trinomial of the form ax^2+bx+c, where |a| ≠ 1 and there are no common factors. To factor this expression, we will rewrite the middle term bx as two terms. The coefficients of these two terms will be factors of ac whose sum must be b.

3n^2( 2n^2+5n-3 ) ⇕ 3n^2( 2n^2+5n+(- 3) ) We have that a= 2, b=5, and c=- 3. There are now a few steps we need to follow in order to rewrite the above expression.

Find a c. Since we have that a= 2 and c=- 3, the value of a c is 2* - 3=- 6.

Since ac=- 6, which is negative, we need factors of a c to have opposite signs — one positive and one negative — in order for the product to be negative. Since b=5, which is positive, the absolute value of the positive factor will need to be greater than the absolute value of the negative factor, so that their sum is positive. c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result - 2 &2 &-2 + 3 &1 2 &- 3 &2 + (-3) &- 1 1 &- 6 &12 + (-6) &- 5 - 1 & 5 & - 1 + 6 &5

Rewrite bx as two terms. Now that we know which factors are the ones to be used, we can rewrite bx as two terms. 3n^2(2n^2+(5)n-3 ) ⇕ 3n^2 ( 2n^2 - 1n + 6n-3 )

Finally, we will factor the last expression obtained.

3n^2( 2n^2-n+6n-3 )

Factor out n

3n^2(n(2n-1))+6n-3 )

Factor out 3

3n^2(n(2n-1))+3(2n-1) )

Factor out (2n-1)

3n^2(n+3)(2n-1)

Checking Our Answer

Check your answer ✓

We can expand our answer and compare it with the given expression.

3n^2(n+3)(2n-1)

Distribute 3n^2

(3n^3+9n^2)(2n-1)

Distribute (3n^3+9n^2)

2n(3n^3+9n^2) -(3n^3+9n^2)

Distribute 2n

6n^4+18n^3-(3n^3+9n^2)

Distribute -1

6n^4+18n^3-3n^3-9n^2

Subtract term

6n^4+15n^3-9n^2

We can see above that after expanding and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!