Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. Exponential Growth and Decay
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Exercise 42 Page 466

An exponential growth function has the form y= ab^x, with a and b being real numbers such that a>0 and b>1.

Example Functions: f(x) = 8(3^x) and g(x) = 27(2^x)

Practice makes perfect
Since we need to find two exponential growth functions f(x) and g(x) with certain conditions, let's first review the format for these type of function. A function that models exponential growth has the following form. y= ab^x Here, a and b are real numbers such that a>0 and b>1. The typical form of the graph of a function like this is shown below.

As we can see from the graph above, these kind of function is increasing in its entire domain. Then, for a function f(x)=a_1b_1^x to be less than a function g(x)=a_2b_2^x for x<3, but also satisfying f(x)>g(x) for x>3, we have three conditions.

  1. The relation for the bases is b_1>b_2. This way f(x) can surpass g(x) for x>3.
  2. Given the first condition, it is only possible to have f(x) < g(x) for x<3, if a_2>a_1.
  3. f(3)=g(3)

There are infinitely many functions that satisfy these conditions. We will show how to find one example. First, let's think about the values for our functions when x= 3. f( 3)= g( 3) ⇒ a_1b_1^3 = a_2b_2^3 In particular, notice that this equality will always hold true if we choose a_1= b_2^3 and a_2= b_1^3, since we would have the identity b_2^3 b_1^3 = b_1^3 b_2^3. Furthermore, since b_1>b_2, with this choice a_2>a_1, as required. Then, we just need to choose the values for b_1 and b_2. Recall that we need to make sure that b_1>b_2.

b_1 1.5cm > 1.5cm b_2
b_1 = 3 b_2 = 2
a_1=b_2^3 a_2=b_1^3
a_1 = 2^3=8 a_2 = 3^3=27
f(x) = a_1b_1^x g(x) = a_2b_2^x
f(x) = 8(3^x) g(x) = 27(2^x)