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If either of the variable terms would cancel out the corresponding variable term in the other equation, you can use the Elimination Method to solve the system.
( 11,-2/5 )
To solve a system of linear equations using the Elimination Method, one of the variable terms needs to be eliminated when one equation is added to or subtracted from the other equation. In this exercise, this means that either the x-terms or the y-terms must cancel each other out.
2 x+5 y=20 & (I) 3 x-10 y=37 & (II)
In its current state, this will not happen. Therefore, we need to find a common multiple between two variable like terms in the system. If we multiply Equation (I) by 2, the y-terms will have opposite coefficients.
(II): Add (I)
We can now solve for y by substituting the value of x into either equation and simplifying.
(I): x= 11
(I): Multiply
(I): LHS-44=RHS-44
(I): .LHS /10.=.RHS /10.
(I): a/b=.a /2./.b /2.
(I): Put minus sign in front of fraction
The solution, or intersection point, of the system of equations is ( 11,- 25).