Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 13 Page 411

Practice makes perfect
a Since the garden has a rectangular form, it has two dimensions: width and length. Hence, we can define two variables, one for each dimension.
&x =width of the rectangular garden &y =length of the rectangular garden With these variables defined, we can imagine that the garden looks as shown below.

Since we are told that "the garden can be no more than 30 ft wide," x must be less than or equal to 30. From this, we get our first inequality. x ≤ 30 On the other hand, in order to enclose the entire garden, the farmer will need 2x+2y ft of chicken wire. But, remember that he "would like to use at most 180 ft of chicken wire," which implies that the perimeter of the rectangle must be less than or equal to 180 ft. Therefore, we have our second inequality. 2x+2y ≤ 180 In conclusion, the system of linear inequalities that models the given situation is as shown below. x≤ 30 2x+2y ≤ 180

b Let's graph the system of inequalities that we created in Part A. We can see that the first inequality involves only the x-variable while the second one involves both x and y-variables.

Graphing Inequality (I)

The equation of the boundary line is found by replacing the inequality symbol with an equals sign. Inequality & Boundary Line x ≤ 30 & x =30 We can see that this is a vertical line whose x-intercept is 30. Additionally, since the inequality is not strict, the boundary line will be solid. The region represented by x ≤ 30 is all the points that are to the left of the boundary line.

Graphing Inequality (II)

We will find the boundary line in the same way for this inequality as well. Inequality & Boundary Line 2x+2y ≤ 180 & 2x+2y = 180 The boundary line is not in slope-intercept form. Let's rewrite it.
2x+2y = 180
â–Ľ
Write in slope-intercept form
2y=180-2x
y=180-2x/2
y=180/2-2x/2
y=90-x
y=- x+90
From this last equation, we can see that the slope of the boundary line is - 1 and the y-intercept is 90. Also, since the initial inequality is not strict (≤), the line will be solid. Let's plot it in the previous coordinate plane.
Now, let's test the origin in the second inequality to determine which region we have to shade. If the point (0,0) produces a true statement, we will shade the region containing it. Otherwise, we will shade the other side of the line.
2x+2y ≤ 180
2( 0)+2( 0) ? ≤ 180
0 ≤ 180
Since 0 is less than or equal to 180, we've got a true statement. Hence, we will shade the region that contains the origin.

Final Graph

Finally, the graph that represents all possible solutions is the overlapping part. But, remember that x and y both represent the dimensions of the garden, so they have to be positive. Therefore, we will limit the region only to the first quadrant.