Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
2. Direct Variation
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Exercise 20 Page 304

What is the form of a direct variation equation?

Equation: y=- 563x
Solution: y=- 224

Practice makes perfect
Direct variation equations are functions where x varies directly with y. They have a specific format. y= mx In this form, m ≠ 0. By substituting the given values for x and y into the equation, we can determine the constant of variation, m.
y=mx
9 13=m( -1/2)
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Solve for m
m(-1/2)=9 13
m(-1/2)=28/3
m=28/3 (- 2)
m=- 56/3
m=-56/3
Now that we have the constant of variation, we can write the function. y= -56/3x Finally, we will substitute 12 for x to find the y-value.
y=-56/3x
y=-56/3 * ( 12)
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Simplify
y=-56* 12/3
y=-56* 4/1
y=- 56* 4
y=- 224
We have found that y=- 224 when x=12.