Pearson Algebra 1 Common Core, 2011
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Exercise 19 Page 231

How many cases do you have after you remove the absolute value?

11/2, 3/2

Practice makes perfect
Before we can solve this equation, we need to isolate the absolute value expression using the Properties of Equality.
5|2x-7|=20
|2x-7|=20/5
|2x-7|=4
An absolute value measures an expression's distance from a midpoint on a number line. |2x-7|= 4 This equation means that the distance is 4, either in the positive direction or the negative direction. |2x-7|= 4 ⇒ l2x-7= 4 2x-7= - 4 To find the solutions to the absolute value equation, we need to solve both of these cases for x.
| 2x-7|=4

lc 2x-7 ≥ 0:2x-7 = 4 & (I) 2x-7 < 0:2x-7 = - 4 & (II)

lc2x-7=4 & (I) 2x-7=- 4 & (II)

(I), (II): LHS+7=RHS+7

l2x=11 2x=3

(I), (II): .LHS /2.=.RHS /2.

lx_1= 112 x_2= 32
Both 112 and 32 are solutions to the absolute value equation.