Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 9 Page 227

Create an or compound inequality because the absolute value is greater than or equal to the given value.

Solution Set: {x | x≤ 2 or x≥ 8}
Graph:

Practice makes perfect
We are asked to find and graph the solution set for all possible values of x in the given inequality. |x-5|≥ 3 To do this, we will create a compound inequality by removing the absolute value. In this case, the solution set is any number that makes the distance between x and 5 greater than or equal to 3 in the positive direction or in the negative direction. x-5 ≥ 3 or x-5≤ - 3

Let's isolate x in both of these cases before graphing the solution set.

Case 1

x-5≥ 3
x≥ 8
The above tells us that all values greater than or equal to 8 will satisfy the first inequality.

Case 2

x-5≤- 3
x≤ 2
The above tells us that all values less than or equal to 2 will satisfy the second inequality.

Solution Set

The solution to this type of compound inequality is the union of the solution sets. First Solution Set:& x≥ 8 Second Solution Set:& x≤ 2 Combined Solution Set:& x≤ 2 or x≥ 8

Graph

The graph of this inequality includes all values less than or equal to 2 or greater than or equal to 8. We show this by keeping the endpoints closed.