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How many cases do you have after you remove the absolute value?
n=13 or n=- 33
First, notice the following.
23=|n+10| ⇔ |n+10|=23
An absolute value measures an expression's distance from a midpoint on a number line.
|n+10|= 23
lc n+10 ≥ 0:n+10 = 23 & (I) n+10 < 0:n+10 = - 23 & (II)
(I), (II): LHS-10=RHS-10
Both n_1=13 and n_2=- 33 solve the equation.
To check those solutions we will substitute them into the original equation. We will start with n_1=13.
We got an identity, therefore the solution is correct. Now, we will substitute n_2=- 33.
Again, we got an identity, therefore the solution is correct.