Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 10 Page 227

Split the compound inequality into two separate inequalities.

Solution Set: - 6 Graph:

Practice makes perfect

We were asked to solve a compound inequality. Let's start by splitting it into separate inequalities. Compound Inequality:&& 9≤ 6-b& < 12 First Inequality:&& 9≤ 6-b& Second Inequality:&& 6-b& < 12 Notice that compound inequalities written in this way are equivalent to compound inequalities that involve the word and. 9≤ 6-b and 6-b < 12Let's solve the inequalities separately.

First Inequality

Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. The only difference is that when you divide or multiply by a negative number, you must flip the inequality sign.

9≤ 6-b
3≤ - b
- 3≥ b
b≤- 3

The above tells us that by all values less than or equal to - 3 will satisfy the first inequality.

Note that the point on - 3 is closed because it is included in the solution set.

Second Inequality

Now, we can solve the second inequality.

6-b<12
- b<6
b>- 6

The above tells us that by all values greater than - 6 will satisfy the second inequality.

Note that the point on - 6 is open because it is not included in the solution set.

Combining Solution Sets

The solution set to the compound inequality is the intersection of the solution sets. First Solution Set: b& ≤ - 3 Second Solution Set: - 6< b& Intersecting Solution Set: -6 < b& ≤ - 3 Finally, we will graph the solution set to the compound inequality on a number line.