body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

5. Samples and Surveys

Continue to next subchapter

Exercise 48 Page 759

Are the variable terms all gathered on one side of the inequality?

x ≥ - 3

Practice makes perfect

Solving inequalities is done in the same way as solving equations, using inverse operations to isolate the variable. Just remember to reverse the inequality symbol when multiplying or dividing the inequality by a negative number.

3(x-2) ≤ 6x+3

Distribute 3

3x-6 ≤ 6x+3

LHS-6x≤RHS-6x

- 3x -6 ≤ 3

LHS+6≤RHS+6

- 3x ≤ 9

Divide by - 3 and flip inequality sign

x ≥ - 3

The above tells us that all the values that satisfy the inequality are greater than or equal to - 3.

Subchapter links

Lesson Check p.756

Practice and Problem-Solving Exercises p.756-759

Standardized Test Prep p.759

Mixed Review p.759