Pearson Algebra 1 Common Core, 2011
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Exercise 25 Page 719

When is a solution of an equation extraneous?

Exactly One Solution: All real numbers except 3
No Solutions: a=3

Practice makes perfect
We are given the following rational equation and asked to make some determinations about the number of solutions based on the value of a. 3/x- a=x/x- a Note that x is the variable of this equation and a is an unknown constant. Let's start by simplifying our equation by multiplying both sides of the equation by x- a.
3/x-a=x/x-a
3/x-a*(x-a)=x/x-a*(x-a)
3=x
x=3

We have that x is equal to 3. Therefore, x=3 is the only potential solution of this equation. However, this value is not always a solution of the original equation! When dealing with rational equations we have to remember to consider the possibility of extraneous solutions.

An extraneous solution is a solution that is derived from the original equation, but it is not actually a solution.

In our equation, a solution is extraneous when it makes the denominator in the original equation equal to 0. x- a=0 ⇔ x= a Let's summarize what we already know.

  • There is one potential solution of the given equation, x=3.
  • A solution of our equation is extraneous if and only if it is equal to a.

We will use this information to determine the values of a for which the equation has exactly one solution and for which it has no solutions.

Exactly One Solution

For this equation, when x=3 is not an extraneous solution, it is the only solution of the original equation. Also, in this case, a solution is extraneous if and only if it is equal to a. Therefore, a solution is not extraneous if and only if it is not equal to a. x= 3 isnotan extraneous solution ⇕ a≠ 3 We have that our equation has exactly one solution for any value of a that is different from 3.

No Solutions

Conversely to the above explanation, when x=3 is an extraneous solution, the equation has no solutions. Again, a solution is extraneous if and only if it is equal to a. x= 3 is an extraneous solution ⇕ a= 3 We have that our equation has no solutions for a=3.