Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Chapter Test
Continue to next subchapter

Exercise 4 Page 719

Just like with fractions, we cannot divide by 0 in rational functions.

3/2

Practice makes perfect

Consider the given rational function. y=2x/8x-12 To identify the excluded value, we must remember that the denominator cannot be 0 because division by 0 is not defined. Let's find the value of x that would make the denominator equal to 0.

8x-12=0
8x=12
x=12/8
x=3/2

If x= 32, the value of the denominator is 0. Therefore, the excluded value is x= 32.