Use the points you create in the table to help you form your equation and graph.
Table:
Bea's Age
4
5
6
7
Ty's Age
1
2
3
4
Equation: y=x-3 Graph:
Practice makes perfect
We are told that Ty is 3 years younger than Bea. This means that whatever age Bea is, we should subtract 3 from it to find Ty's age. Let's test a few of Bea's ages in a table of values and see how old Ty is at each of those. We will let the variable x represent Bea's age and the variable y will represent Ty's age.
Bea's Age
4
5
6
7
...
x
Bea's Age -3
4-3
5-3
6-3
7-3
...
x-3
Ty's Age
1
2
3
4
...
y
Looking at our table, we can see that Ty's Age y is equal to 3 less than Bea's Age x. Let's use this verbal expression to construct an algebraicequation.
Ty's age is 3 less than Bea's age
y = x - 3
Now, we can use the points we determined in the table above to draw a graph. We will first plot the points, then draw a line connecting them. We can draw a line because a person's age can be any positivereal number.
