Exercise 10 Page 273

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side, using the Properties of Equality. In this case, we need to start by using the Distributive Property to simplify the left-hand side of the equation.

3(11x-7)=13x+25

Distr

Distribute 3

33x-21=13x+25

Now we can continue to solve using the Properties of Equality.

33x-21=13x+25

SubEqn

LHS-13x=RHS-13x

33x-21-13x=13x+25-13x

SubTerms

Subtract terms

20x-21=25

AddEqn

LHS+21=RHS+21

20x-21+21=25+21

AddTerms

Add terms

20x=46

DivEqn

.LHS /20.=.RHS /20.

20x/20=46/20

CalcQuot

Calculate quotient

x=46/20

ReduceFrac

a/b=.a /2./.b /2.

x=23/10

The solution to the equation is x= 2310.