2. Algebraic Proof
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Write the relationship as reflexive, symmetric and transitive to check whether the properties satisfy the relationship.
It is not an equivalence relation.
≈ Let's examine the relationship.
Property | Expression of Property | Relationship | Result | Explanation |
---|---|---|---|---|
Reflexive | a=a | a ≈ a | Reflexive property does not satisfy the relationship. | a is not approximately a, a is equal to a. |
Symmetric | If a=b, then b=a. | If a≈ b, then b≈ a. | Symmetric property satisfies the relationship. | |
Transitive | If a=b and b=c, then a=c. | If a≈ b and b≈ c, then a≈ c. | Transitive property satisfies the relationship. |
As a result the relationship is not reflexive. Therefore, it is not an equivalence relation.