McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
2. Solving Quadratic Equations by Graphing
Continue to next subchapter

Exercise 3 Page 108

Begin by writing the terms on the left-hand side. Then, identify the values of a, b, and c.

Graph:

Solution: x=-2

Practice makes perfect
We want to solve the given quadratic equation by graphing. Let's begin by writing the terms on the left-hand side. x^2+4x=-4 ⇔ x^2+4x+4=0 To solve the equation, we will graph the quadratic function represented by the left-hand side of the above equation. To draw the graph, we must start by identifying the values of a, b, and c. y=x^2+4x+4 ⇔ y= 1x^2+ 4x+ 4

We can see that a= 1, b= 4, and c= 4. Now, we will follow four steps to graph the function.

  1. Find the axis of symmetry.
  2. Calculate the vertex.
  3. Identify the y-intercept and its reflection across the axis of symmetry.
  4. Connect the points with a parabola.

Finding the Axis of Symmetry

The axis of symmetry is a vertical line with equation x=- b2 a. Since we already know the values of a and b, we can substitute them into the formula.
x=- b/2a
x=- 4/2( 1)
x=- 4/2
x=-2
The axis of symmetry of the parabola is the vertical line with equation x=-2.

Calculating the Vertex

To calculate the vertex, we need to think of y as a function of x, y=f(x). We can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex: ( - b/2 a, f( - b/2 a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x=- 2. Thus, the x-coordinate of the vertex is also - 2. To find the y-coordinate, we need to substitute - 2 for x in our function.
y=x^2+4x+4
y=( -2)^2+4( -2)+4
â–Ľ
Simplify right-hand side
y=4+4(-2)+4
y=4-8+4
y=0
We found the y-coordinate, and now we know that the vertex is (-2,0).

Identifying the y-intercept and its Reflection

The y-intercept of the graph of a quadratic function written in standard form is given by the value of c. Thus, the point where our graph intercepts the y-axis is (0, 4). Let's plot this point and its reflection across the axis of symmetry.

Connecting the Points

We can now draw the graph of the function. Since a= 1, which is positive, the parabola will open upward. Let's connect the three points with a smooth curve.

The x-intercepts of the graph are the solutions to the given equation. By looking at the graph, we can state the values for the x-intercepts. Notice that the vertex of the parabola is the only x-intercept. Therefore, there is only one solution, which is x=-2.