News
Get Premium
Dashboard
Dashboard Sign out
McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
7. Special Segments in a Circle
Continue to next subchapter
search

Exercise 31 Page 773

Notice that the segments are chords and use the Segments of Chords Theorem.

Example answer: The products of the lengths of the chord segments are equal.

Practice makes perfect

Let's consider a circle and two secants that intersect inside the circle.

As we can see, in this case, the segments formed by the two secants are in fact chords.

By the Segments of Chords Theorem the products of the lengths of the chord segments are equal. AE * EB = CE * ED

Subchapter links expand_more
arrow_right Exercises p.771-774
1
Exercises 2 (Page 771)
Exercises 3 (Page 771)
Exercises 4 (Page 771)
Exercises 5 (Page 771)
Exercises 6 (Page 772)
Exercises 7 (Page 772)
Exercises 8 (Page 772)
Exercises 9 (Page 772)
Exercises 10 (Page 772)
Exercises 11 (Page 772)
Exercises 12 (Page 772)
Exercises 13 (Page 772)
Exercises 14 (Page 772)
Exercises 15 (Page 772)
Exercises 16 (Page 772)
Exercises 17 (Page 772)
Exercises 18 (Page 772)
Exercises 19 (Page 772)
Exercises 20 (Page 772)
Exercises 21 (Page 772)
Exercises 22 (Page 773)
Exercises 23 (Page 773) engineering
Exercises 24 (Page 773) engineering
Exercises 25 (Page 773) engineering
Exercises 26 (Page 773)
Exercises 27 (Page 773)
Exercises 28 (Page 773)
Exercises 29 (Page 773)
Exercises 30 (Page 773) engineering
Exercises 31 (Page 773)
Exercises 32 (Page 774)
Exercises 33 (Page 774)
Exercises 34 (Page 774)
Exercises 35 (Page 774)
Exercises 36 (Page 774)
Exercises 37 (Page 774)
Exercises 38 (Page 774)
Exercises 39 (Page 774)
Exercises 40 (Page 774)
41 engineering
42 engineering
43 engineering
Exercises 44 (Page 774)
Exercises 45 (Page 774)
Exercises 46 (Page 774)
Exercises 47 (Page 774)
Exercises 48 (Page 774)
Exercises 49 (Page 774)