McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Special Products
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Exercise 51 Page 32

f^3+f^2g -fg^2-g^3

Practice makes perfect
To simplify the given expression we will use the Distributive Property.
(f+g)(f-g)(f+g)
(f+g) ( f(f+g)-g(f+g) )
â–Ľ
Distribute f & - g
(f+g) ( f^2+fg-g(f+g) )
(f+g) ( f^2+fg-fg-g^2 )
(f+g) ( f^2-g^2 )
f^2 ( f+g ) -g^2( f+g)
â–Ľ
Distribute f^2 & - g^2
f^3+f^2g -g^2( f+g)
f^3+f^2g -fg^2-g^3

Alternative Solution

Using the Difference of Squares
We can also simplify the expression by using the difference of squares.
(f+g)(f-g)(f+g)
( f^2-g^2 ) (f+g)
f^2(f+g)-g^2(f+g)
â–Ľ
Distribute f^2 & - g^2
f^3+f^2g-g^2(f+g)
f^3+f^2g-fg^2-g^3