McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
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Exercise 39 Page 31

64a^4-81b^6

Practice makes perfect
Notice that the given expression is the multiplication of conjugates. This allows us to use a shorter method of multiplying the terms than the normal distribution process.
(8a^2-9b^3)(8a^2+9b^3)

(a-b)(a+b)=a^2-b^2

(8a^2)^2-(9b^3)^2
8^2(a^2)^2-9^2(b^3)^2
8^2a^4-9^2b^6
64a^4-81b^6