McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
Mid-Chapter Quiz
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Exercise 34 Page 34

a Let's start this with the formula for the area of a circle and r=x+3.25
cc A &=& π r^2 &=& π (x+3.25)^2 Now that is one way to express the area of the largest disc. We can also expand that binomial using the Distributive Property for the second expression of the area.
π (x+3.25)^2
Simplify right-hand side
π (x^2 + 2 * 3.25x + 3.25^2)
π (x^2 + 2 * 3.25x + 10.5625)
π(x^2 + 6.5x + 10.5625)
π x^2 + 6.5π x + 10.5625 π
That is the second answer.
b To find the area of the disc, we can use the area formula once we determine the radius for each disc. The smallest disc has a radius of x in. Since we are given that x=10.5, we can use that to find the area of the smallest disc.
A = π r^2
A = π ( 10.5)^2
Simplify right-hand side
A = π * 110.25
A ≈ (3.14)(110.25)
A ≈ 346.185
The smallest disc can have an area of 110.25 π ≈ 346.185 in^2. The largest disc has an expression for it's radius of x+3.25 in. Let's substitute x=10.5 to get it's radius.
A = π r^2
A = π ( x+3.25)^2
Simplify right-hand side
A = π ( 10.5+3.25)^2
A = π (13.75)^2
A = π (189.0625)
A ≈ 3.14 (189.0625)
A ≈ 593.65625

We can say that the largest disc has an area of 189.0625 π which is about 593.656 in^2.