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| | 9 Theory slides |
| | 9 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Consider two different polynomials P(x) and Q(x). P(x) &= 5x^3-2x+7 [0.1cm] Q(x) &= 3(x-1)(x+4) Is it possible to calculate the sum and the difference of P(x) and Q(x)? Are the obtained results also polynomials? If yes, what is the degree, the leading coefficient, and the constant term of P(x)+Q(x)?
Given two polynomials, their sum or difference can be calculated. Consider the following pair of polynomials. - 2x^2 + x + 3 and 2x^2 + 4x - 10 In order to add these polynomials, there are three steps to follow. Note that subtraction of the polynomials can be performed by applying the same three steps, only instead of adding the like terms, they will be subtracted.
Remove parentheses
Commutative Property of Addition
When subtracting polynomials, remember to distribute - 1 to the terms of the second polynomial before rearranging the terms.
Remove parentheses
Distribute - 1
Commutative Property of Addition
Therefore, the sum is 5x-7. Note that the given polynomials are of degree 2. However, the new polynomial is of degree 1 because the x^2-terms canceled each other out. If they had not canceled each other out, the new polynomial would have also been of degree 2.
Is the result of addition or subtraction of polynomials always another polynomial? This can be verified by analyzing the sum of two arbitrary polynomials. 3x^3+5x^2-x+7 and 12x^2+6x-3 To add these polynomials, their like terms will be rearranged to be next to each other and then added.
Remove parentheses
Commutative Property of Addition
Add and subtract terms
Dylan's family is moving into an apartment. He is curious about how many people live in apartements as opposed to houses. He finds a study that states that during a 6-year period, the amounts of money in millions of dollars spent on buying houses B and renting houses R by United States residents are modeled by the following two polynomials.
B&=- 0.023n^3+0.08n^2+0.1n+15 R&=- 0.41n^2+1.3n+36 Here, n=1 represents the first year in the 6-year period.
Remove parentheses
Commutative Property of Addition
Add and subtract terms
a+(- b)=a-b
Note that the polynomial is written in standard form as the degrees of its monomials decrease moving from left to right.
- &0.41n^2+1.3n+36 + (- 0.023n^3+&0.08n^2+0.1n+15) - 0.023n^3-&0.33n^2+1.4n+51
B + R = - 0.023n^3 - 0.33n^2 + 1.4n + 51 R + B = - 0.023n^3 - 0.33n^2 + 1.4n + 51 As can be seen, these sums are the same polynomial. Recall that addition of real numbers is commutative. Since adding polynomials comes down to adding the coefficients of like terms, which are real numbers, it can be concluded that the addition of polynomials is also commutative.
- 0.023n^3-0.33n^2+1.4n+51 Therefore, the degree of this polynomial is 3. The leading coefficient of a polynomial is the coefficient of the term with the highest degree. Since the first term has the highest degree, the leading coefficient is - 0.023. - 0.023n^3-0.33n^2+1.4n+51
Dylan is delighted to find out that one of his classmates lives in his apartment building, although they live on different floors. They decided to run a little experiment for their science class. Both of them would drop an object from their window at the same time and would see whose object reached the ground first.
Substitute expressions
Remove parentheses
Distribute - 1
Commutative Property of Addition
Add and subtract terms
- 16x^2+ 0x&+100 - - 16x^2-45x &+180 45x &- 80
T(x)-P(x)&=- 45x+80 P(x)-T(x)&=45x-80 The polynomials are different. This suggests that when subtracting polynomials, their order does matter. In other words, the subtraction of polynomials is not commutative.
T(x)-P(x)&=- 45x^1+80 P(x)-T(x)&=45x^1-80 The degree of each polynomial is 1. Next, recall that the leading coefficient of a polynomial is the coefficient of the term with the highest degree. T(x)-P(x)&= - 45x+80 P(x)-T(x)&= 45x-80 In the first polynomial, the leading coefficient is - 45, while it is 45 in the second polynomial.
Consider the sum or difference of the given polynomials. Identify their degree or leading coefficient.
In the evening, Dylan is reading his apartment complex's newsletter on his tablet and finds a small mathematical riddle. Readers who solve it correctly can get a 50 % discount for a highly innovative online course called Smart Applications of Math.
The polynomial corresponding to P-Q-R can be calculated in a similar manner, this time subtracting the terms. Consider how the sign of each term might be affected by the subtraction sign — remember, subtracting a negative number is the same as adding the terms. There are three rows of polynomials, but the subtraction will be done by considering only two terms at a time.
Next, the polynomial Q will be added to P and then R will be subtracted. Remember to carefully consider the signs of the terms when subtracting R.
Finally, the polynomial P-Q+R will be calculated.
With the information presented in the lesson, the challenge given in the beginning can finally be solved. The challenge was to calculate the sum and the difference of the two given polynomials P(x) and Q(x). P(x) &= 5x^3-2x+7 [0.1cm] Q(x) &= 3(x-1)(x+4) Furthermore, if P(x)+Q(x) is also a polynomial, what are its degree, leading coefficient, and constant term?
Substitute expressions
Commutative Property of Addition
Add and subtract terms
By the Closure Property of Polynomial Addition, the obtained result is also a polynomial. The highest degree of its monomials is 3, so 3 is the degree of P(x)+Q(x). The coefficient of the monomial with the highest degree is 5, so the leading coefficient is 5. Moreover, the constant term is - 5.
Now, the difference of P(x) and Q(x) can be found following a similar procedure. For simplicity, the previously found standard form of Q(x) will be used.
Substitute expressions
Remove parentheses
Distribute - 1
Commutative Property of Addition
Add and subtract terms
The obtained expression consists of monomials, so it is also a polynomial. P(x) + Q(x)& = 5x^3 + 3x^2 + 7x - 5 P(x) - Q(x)& = 5x^3 - 3x^2 - 11 x+ 19
Write the polynomial, in standard form, that represents the perimeter of the quadrilateral shown in the diagram.
The perimeter of a polygon is calculated by adding all the side lengths of the polygon. Therefore, to find the perimeter of the given quadrilateral, we will add all four side lengths together. Then we will simplify the resulting expression by adding and subtracting like terms. Let's do it!
We found that the perimeter of the given quadrilateral is 16x-7 units. Perimeter 16x-7 Keep in mind that although it is not stated, x must be a real number such that all four side lengths and the perimeter are positive. Side Length I:& 3x>0 Side Length II:& - x^2+4x-3>0 Side Length III:& 3x-1>0 Side Length IV:& x^2+6x-3>0 Perimeter:& 16x-7>0 We should disregard all values of x that make any of the above expressions non-positive. For example, x cannot be non-negative because if that were the case, the expression 3x would be non-positive.
By its own definition, a binomial is the sum of two monomials. Also, we know that the degree of a binomial is the greatest degree of the monomials. If the degree of a monomial is zero, then it is a constant. Therefore, if the degree of a binomial is zero, then it is the sum of two constants. Binomial = Constant + Constant Since the sum of two constants is also a constant, the resulting expression has only one term and therefore is not a binomial — in other words, it is a monomial. Constant=Monomial As such, we can conclude that a binomial cannot have a degree of zero. This means that the given statement is false.
To verify whether the given statement is true or false, let's consider two arbitrarily chosen polynomials.
P(x) = x^2 + 1 and Q(x) = x^2 - 1
First, let's calculate P(x)-Q(x).
Next, let's calculate the subtraction in the opposite order, Q(x)-P(x).
As we can see, the results are different. Therefore, the order in which polynomials are subtracted is relevant. This means that the given statement is false.