body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Recommended

Tests

An error ocurred, try again later!

eCourses /

Algebra 1 /

Chapter {{ article.chapter.number }}

{{ article.number }}.

Show less Show more

Lesson Settings & Tools

	{{ 'ml-lesson-number-slides' \| message : article.intro.bblockCount }}
	{{ 'ml-lesson-number-exercises' \| message : article.intro.exerciseCount }}
	{{ 'ml-lesson-time-estimation' \| message }}

Image Credits

{{ item.file.title }}
{{ presentation }}

No file copyrights entries found

Polynomials are often applied to solve real-life problems. In many situations, more than one polynomial is used. In such cases, it can be useful to calculate the sum or the difference of two or more polynomials. In this lesson, the procedure of adding and subtracting polynomials will be presented and practiced.

Catch-Up and Review

Here are a few recommended readings before getting started with this lesson.

Polynomial
Degree of a Monomial
Standard Form of a Polynomial
Like Terms
Combining Like Terms

Challenge

Investigating Polynomial Sum and Difference

Consider two different polynomials

P (x)

and

Q (x) .

P (x) Q (x) = 5 x^{3} - 2 x + 7 = 3 (x - 1) (x + 4)

Is it possible to calculate the sum and the difference of

P (x)

and

Q (x) ?

Are the obtained results also polynomials? If yes, what is the degree, the leading coefficient, and the constant term of

P (x) + Q (x) ?

Discussion

Adding and Subtracting Polynomials

Given two polynomials, their sum or difference can be calculated. Consider the following pair of polynomials.

- 2 x^{2} + x + 3 and 2 x^{2} + 4 x - 10

In order to add these polynomials, there are three steps to follow. Note that subtraction of the polynomials can be performed by applying the same three steps, only instead of adding the like terms, they will be subtracted.

Rearrange Terms

Generally speaking, polynomials are added by adding their like terms. Therefore, it can be helpful to rearrange the terms so that the like terms are next to each other.

(- 2 x^{2} + x + 3) + (2 x^{2} + 4 x - 10)

RemovePar

Remove parentheses

- 2 x^{2} + x + 3 + 2 x^{2} + 4 x - 10

CommutativePropAdd

Commutative Property of Addition

(- 2 x^{2} + 2 x^{2}) + (x + 4 x) + (3 - 10)

When subtracting polynomials, remember to distribute

- 1

to the terms of the second polynomial before rearranging the terms.

(- 2 x^{2} + x + 3) - (2 x^{2} + 4 x - 10)

RemovePar

Remove parentheses

- 2 x^{2} + x + 3 - (2 x^{2} + 4 x - 10)

Distr

Distribute $- 1$

- 2 x^{2} + x + 3 - 2 x^{2} - 4 x + 10

CommutativePropAdd

Commutative Property of Addition

(- 2 x^{2} - 2 x^{2}) + (x - 4 x) + (3 + 10)

Add and Subtract Like Terms

Next, the like terms can be combined. In other words, the monomials should be added or subtracted by adding or subtracting their coefficients.

(- 2 x^{2} + 2 x^{2}) + (x + 4 x) + (3 - 10)

AddSubTerms

Add and subtract terms

0 x^{2} + 5 x + (- 7)

Simplify the Result

Finally, the obtained result of addition can be simplified. For example, since the coefficient before

x^{2} -

term is

0,

this term is equal to

0

and can be omitted.

0 x^{2} + 5 x + (- 7)

ZeroPropMult

Zero Property of Multiplication

5 x + (- 7)

AddNeg

$a + (- b) = a - b$

5 x - 7

Therefore, the sum is

5 x - 7 .

Note that the given polynomials are of degree

2 .

However, the new polynomial is of degree

1

because the

x^{2} -

terms canceled each other out. If they had not canceled each other out, the new polynomial would have also been of degree

2 .

When adding or subtracting two polynomials of degrees

m

and

n,

the degree of the resulting polynomial is at most the equal to the degree of higher degree polynomial.

Extra

Vertical Format of Addition and Subtraction

Previously, polynomials were added by using the horizontal format. The vertical format of polynomial addition or subtraction will now be presented. Note that for this method, the like terms should be aligned vertically.

+ - 2 x^{2} + x + 3 - 2 x^{2} + 4 x - 10 - 0 x^{2} + 5 x - 7 (

By comparing the results, it can be concluded that no matter which format of addition is used, the sums are the same.

Discussion

Closure Property of Polynomial Addition and Subtraction

Is the result of addition or subtraction of polynomials always another polynomial? This can be verified by analyzing the sum of two arbitrary polynomials.

3 x^{3} + 5 x^{2} - x + 7 and 12 x^{2} + 6 x - 3

To add these polynomials, their like terms will be rearranged to be next to each other and then added.

(3 x^{3} + 5 x^{2} - x + 7) + (12 x^{2} + 6 x - 3)

RemovePar

Remove parentheses

3 x^{3} + 5 x^{2} - x + 7 + 12 x^{2} + 6 x - 3

CommutativePropAdd

Commutative Property of Addition

3 x^{3} + (5 x^{2} + 12 x^{2}) + (- x + 6 x) + (7 - 3)

AddSubTerms

Add and subtract terms

3 x^{3} + 17 x^{2} + 5 x + 4

This expression seems to be a polynomial. To show that it is in fact a polynomial, consider a general case of adding two polynomials.

Note that adding two polynomials comes down to adding their monomials. Since a sum of two or more monomials is always a monomial, the result of adding two polynomials is an expression containing monomials. It is, by definition, a polynomial. Adding or subtracting polynomials results in another polynomial, which means that polynomials are closed under addition and subtraction.

Example

Adding Polynomials in Different Order and Formats

Dylan's family is moving into an apartment. He is curious about how many people live in apartements as opposed to houses. He finds a study that states that during a $6 -$ year period, the amounts of money in millions of dollars spent on buying houses $B$ and renting houses $R$ by United States residents are modeled by the following two polynomials.

B R = - 0.023 n^{3} + 0.08 n^{2} + 0.1 n + 15 = - 0.41 n^{2} + 1.3 n + 36

Here,

n = 1

represents the first year in the

6 -

year period.

a Calculate

B + R .

Express the polynomial in standard form.

b Calculate

R + B .

Express the polynomial in standard form.

c Compare

B + R

and

R + B .

Are the sums the same or different?

d What are the degrees of the calculated sums?

What are their leading coefficients?

Hint

a Start by rearranging like terms so that they are situated next to each other.

b Add the polynomials by adding their like terms. Use either the horizontal or vertical format of addition.

c Compare the sums obtained in Parts A and B. Does it matter in which order the polynomials are added?

d Recall the definitions of the degree and the leading coefficient of a polynomial.

Solution

a In order to add the two given polynomials, rearrange the terms so that like terms are next to each other. Then, add the like terms and simplify the sum.

(- 0.023 n^{3} + 0.08 n^{2} + 0.1 n + 15) + (- 0.41 n^{2} + 1.3 n + 36)

RemovePar

Remove parentheses

- 0.023 n^{3} + 0.08 n^{2} + 0.1 n + 15 - 0.41 n^{2} + 1.3 n + 36

CommutativePropAdd

Commutative Property of Addition

- 0.023 n^{3} + (0.08 n^{2} - 0.41 n^{2}) + (0.1 n + 1.3 n) + (15 + 36)

AddSubTerms

Add and subtract terms

- 0.023 n^{3} + (- 0.33 n^{2}) + 1.4 n + 51

AddNeg

$a + (- b) = a - b$

- 0.023 n^{3} - 0.33 n^{2} + 1.4 n + 51

Note that the polynomial is written in standard form as the degrees of its monomials decrease moving from left to right.

b To find the sum of

R + B,

the polynomials will be added using the vertical format of polynomial addition. Again, the sum can be found by adding the like terms of the polynomials. To perform the addition correctly, do not forget to align the like terms vertically.

l a l a l a l a a (- + (- 0.023 n^{3} + (- 0.023 n^{3} - 0.41 n^{2} + 1.3 n + 36 0.08 n^{2} + 0.1 n + 15) 0.33 n^{2} + 1.4 n + 51

c Now, the sums found in Parts A and B can be compared.

B + R = - 0.023 n^{3} - 0.33 n^{2} + 1.4 n + 51 R + B = - 0.023 n^{3} - 0.33 n^{2} + 1.4 n + 51

As can be seen, these sums are the same polynomial. Recall that addition of real numbers is commutative. Since adding polynomials comes down to adding the coefficients of like terms, which are real numbers, it can be concluded that the addition of polynomials is also commutative.

d Recall that the degree of a polynomial is the highest degree of its monomials. In this case, the first monomial has the

highest

degree,

which is

3 .

- 0.023 n^{3} - 0.33 n^{2} + 1.4 n + 51

Therefore, the degree of this polynomial is

3 .

The leading coefficient of a polynomial is the coefficient of the term with the highest degree. Since the first term has the highest degree, the

leading

coefficient

- 0.023 .

- 0.023 n^{3} - 0.33 n^{2} + 1.4 n + 51

Example

Subtracting Polynomials to Solve a Real-Life Problem

Dylan is delighted to find out that one of his classmates lives in his apartment building, although they live on different floors. They decided to run a little experiment for their science class. Both of them would drop an object from their window at the same time and would see whose object reached the ground first.

Teddy bear and pencil are dropped from different height

External credits: @freepik

The following two polynomials

T

and

P

represent the height of the teddy bear and the pencil

x

seconds after being released, respectively.

T (x) P (x) = - 16 x^{2} - 45 x + 180 = - 16 x^{2} + 100

a Write the simplified polynomial that represents the difference between the heights of the teddy bear and the pencil

x

seconds after being dropped.

b Calculate

P (x) - T (x) .

Express the polynomial in standard form.

c Compare

T (x) - P (x)

and

P (x) - T (x) .

Are these differences the same or different?

d What are the degrees of the calculated differences?

What are their leading coefficients?

Hint

a First, rearrange the like terms so that they are situated next to each other, then add them.

b Subtract the polynomials by subtracting their like terms. Use either the horizontal or vertical format of subtraction.

c Compare the results obtained in Parts A and B. Does the order in which the polynomials are subtracted matter?

d Use the definitions of the degree and the leading coefficient of a polynomial.

Solution

a To subtract the two given polynomials, rearrange the terms so that like terms are next to each other. Next, add the like terms and simplify the difference.

T (x) - P (x)

SubstituteExpressions

Substitute expressions

(- 16 x^{2} - 45 x + 180) - (- 16 x^{2} + 100)

RemovePar

Remove parentheses

- 16 x^{2} - 45 x + 180 - (- 16 x^{2} + 100)

Distr

Distribute $- 1$

- 16 x^{2} - 45 x + 180 + 16 x^{2} - 100

CommutativePropAdd

Commutative Property of Addition

(- 16 x^{2} + 16 x^{2}) - 45 x + (180 - 100)

AddSubTerms

Add and subtract terms

- 45 x + 80

b To find the polynomial that represents the difference

P (x) - T (x),

align the like terms of the polynomials vertically and then subtract them.

c Now, the differences found in Parts A and B can be compared.

T (x) - P (x) P (x) - T (x) = - 45 x + 80 = 45 x - 80

The polynomials are different. This suggests that when subtracting polynomials, their order does matter. In other words, the subtraction of polynomials is not commutative.

d To determine the

degrees

of the polynomials, look for the highest degree of their monomials.

T (x) - P (x) P (x) - T (x) = - 45 x^{1} + 80 = 45 x^{1} - 80

The degree of each polynomial is

1 .

Next, recall that the leading coefficient of a polynomial is the coefficient of the term with the highest degree.

T (x) - P (x) P (x) - T (x) = - 45 x + 80 = 45 x - 80

In the first polynomial, the leading coefficient is

- 45,

while it is

45

in the second polynomial.

Pop Quiz

Determining the Degree and Leading Coefficient of Polynomials

Consider the sum or difference of the given polynomials. Identify their degree or leading coefficient.

Two different polynomials are generated randomly

Example

Solving a Riddle to Win a Prize

In the evening, Dylan is reading his apartment complex's newsletter on his tablet and finds a small mathematical riddle. Readers who solve it correctly can get a

50 %

discount for a highly innovative online course called Smart Applications of Math.

The three polynomials P(n)=8n^4-3n^2-11n+42, Q(n)=7n^6+n^4-3n^3+2, and R(n)=12n^5+4n^3-5n^2+7n are written in the newspaper

Dylan really likes studying mathematics, so he eagerly starts solving the riddle.

A . B . C . D . 7 n^{6} + 12 n^{5} + 9 n^{4} + n^{3} - 8 n^{2} - 4 n + 44 - 7 n^{6} - 12 n^{5} + 7 n^{4} - n^{3} + 2 n^{2} - 18 n + 40 7 n^{6} - 12 n^{5} + 9 n^{4} - 7 n^{3} + 2 n^{2} - 18 n + 44 - 7 n^{6} + 12 n^{5} + 7 n^{4} + 7 n^{3} - 8 n^{2} - 4 n + 40

Help him match the equivalent polynomials.

Hint

In order to add or subtract polynomials, align the like terms vertically and then perform the addition or subtraction.

Solution

First, the sum of the three given polynomials can be found. In order to add polynomials, align the alike terms vertically and add them.

The polynomial corresponding to

P - Q - R

can be calculated in a similar manner, this time subtracting the terms. Consider how the sign of each term might be affected by the subtraction sign — remember, subtracting a negative number is the same as adding the terms. There are three rows of polynomials, but the subtraction will be done by considering only two terms at a time.

Next, the polynomial

Q

will be added to

P

and then

R

will be subtracted. Remember to carefully consider the signs of the terms when subtracting

R .

Finally, the polynomial

P - Q + R

will be calculated.

Closure

Calculating the Sum and Difference of Two Polynomials

With the information presented in the lesson, the challenge given in the beginning can finally be solved. The challenge was to calculate the sum and the difference of the two given polynomials

P (x)

and

Q (x) .

P (x) Q (x) = 5 x^{3} - 2 x + 7 = 3 (x - 1) (x + 4)

Furthermore, if

P (x) + Q (x)

is also a polynomial, what are its degree, leading coefficient, and constant term?

Hint

First, rewrite $Q (x)$ in standard form. Then add and subtract the polynomials by adding and subtracting their like terms.

Solution

First, the sum of the polynomials will be calculated. Note that the second polynomial is not written in standard form, so it has to be rewritten first. To add these polynomials, the horizontal format of addition will be used. Like terms should be rearranged to be next to each other and then combined.

P (x) + Q (x)

SubstituteExpressions

Substitute expressions

(5 x^{3} - 2 x + 7) + 3 (x - 1) (x + 4)

▼

Rewrite

MultPar

Multiply parentheses

(5 x^{3} - 2 x + 7) + 3 (x^{2} + 4 x - x - 4)

SubTerm

Subtract term

(5 x^{3} - 2 x + 7) + 3 (x^{2} + 3 x - 4)

Distr

Distribute $3$

(5 x^{3} - 2 x + 7) + 3 x^{2} + 9 x - 12

RemovePar

Remove parentheses

5 x^{3} - 2 x + 7 + 3 x^{2} + 9 x - 12

CommutativePropAdd

Commutative Property of Addition

5 x^{3} + 3 x^{2} + (- 2 x + 9 x) + (7 - 12)

AddSubTerms

Add and subtract terms

5 x^{3} + 3 x^{2} + 7 x - 5

By the Closure Property of Polynomial Addition, the obtained result is also a polynomial. The highest degree of its monomials is

3,

3

is the degree of

P (x) + Q (x) .

The coefficient of the monomial with the highest degree is

5,

so the leading coefficient is

5 .

Moreover, the constant term is

- 5 .

Now, the difference of

P (x)

and

Q (x)

can be found following a similar procedure. For simplicity, the previously found standard form of

Q (x)

will be used.

P (x) - Q (x)

SubstituteExpressions

Substitute expressions

(5 x^{3} - 2 x + 7) - (3 x^{2} + 9 x - 12)

RemovePar

Remove parentheses

5 x^{3} - 2 x + 7 - (3 x^{2} + 9 x - 12)

Distr

Distribute $- 1$

5 x^{3} - 2 x + 7 - 3 x^{2} - 9 x + 12

CommutativePropAdd

Commutative Property of Addition

5 x^{3} - 3 x^{2} + (- 2 x - 9 x) + (7 + 12)

AddSubTerms

Add and subtract terms

5 x^{3} - 3 x^{2} - 11 x + 19

The obtained expression consists of monomials, so it is also a polynomial.

P (x) + Q (x) P (x) - Q (x) = 5 x^{3} + 3 x^{2} + 7 x - 5 = 5 x^{3} - 3 x^{2} - 11 x + 19

Loading content

{{ article.displayTitle }}

Catch-Up and Review

Extra

Hint

Solution

Hint

Solution

Hint

Solution

Hint

Solution