We are given a figure that contains at least four and asked to find the value of x. Let's look at the picture and name all of the missing sides with the consecutive letters.
Our first step will be to evaluate the value of a.
To do this, we will use the . According to this theorem, the sum of the squared legs of a is equal to its squared .
7.5^2+ a^2= 11.6^2
Now, we will solve the above equation. Remember that if we are taking a square root of a squared number that represents a side length, we consider only the positive case.
7.5^2+a^2=11.6^2
56.25+a^2=134.56
a^2=78.31
sqrt(a^2)=sqrt(78.31)
a=sqrt(78.31)
a=8.8492...
a≈8.85
The value of a is approximately 8.85. Next we can solve for b.
To do this, we will again use the .
8.85^2+ 15^2= b^2
Let's solve the above equation.
8.85^2+15^2=b^2
78.31+225=b^2
303.31=b^2
b^2=303.31
sqrt(b^2)=sqrt(303.31)
b=sqrt(303.31)
b=17.4157...
b≈17.42
The value of b is approximately 17.42. Next, notice that we can find the value of c.
We will again create and solve an equation using the .
2.7^2+c^2= 13^2
7.29+c^2=169
c^2=161.71
sqrt(c^2)=sqrt(161.71)
c=sqrt(161.71)
c=12.7165...
c≈12.72
The value of c is approximately 12.72.
Notice that using this value we can find the value of d.
d= 17.42-12.72=4.7
Finally, we can use the value of d to evaluate the value of x.
Let's use the for the last time.
4.7^2+2.7^2=x^2
22.09+7.29=x^2
29.38=x^2
x^2=29.38
sqrt(x^2)=sqrt(29.38)
x=sqrt(29.38)
x=5.42033...
x≈5.4
The value of x is approximately 5.4.