body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Glencoe Geometry, 2012

MH

McGraw Hill Glencoe Geometry, 2012 View details

Study Guide and Review

Continue to next subchapter

Exercise 10 Page 525

Solve for the variable by using cross products.

- 15

Practice makes perfect

To solve the proportion, we will start by using cross products. Remember that we will need to treat the expression 3x+9 as a single quantity in the cross multiplication process.

3x+9/x=12/5

Cross multiply

(3x+9)5=12x

From here, we will continue solving for x by using the Distributive Property and the Properties of Equality.

(3x+9)5=12x

Distribute 5

15x+45=12x

LHS-12x=RHS-12x

3x+45=0

LHS-45=RHS-45

3x=- 45

.LHS /3.=.RHS /3.

x=- 15

Subchapter links

Exercises p.524-528